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1 answer:
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Answer:
change in storage = -310,500 ft^3
intital storage= 3.67 acre ft
Explanation:
Given data:
Rate of inflow = 350 cfs
Rate of outflow = 285 cfs
After 90 min, rate of inflow = 250 cfs
Rate of outflow = 200 cfs
final storage = 10.8 acre-ft
calculating the average inflow and outflow
average inflow
average outlow
total amount of water drain during the period of one hour
= (average outflow - average inflow) *60*90
= (242.5 - 300)*60*90 = -310,500
change in storage is calculate as
= -310,500 ft^3
in cubic meter
= -310500/35.315 = 8792.30 cm^3
in acre-ft
= -310,500/43560 = 7.13 acre ft
initial storage = 10.8 - 7.13 = 3.67 acre ft
Answer:
q = 0.1086 micro Coulombs
Explanation:
By Coulombs law, we have;
Where;
F = The electric force = 120 mgm
q₁ and q₂ = Charge
r = The separating distance = 30 cm = 0.3 m
k = 8.9876×10⁹ kg·m³/(s²·C²)
Where, q₁ and q₂, we have;
Whereby the force is the force of 120 milligram mass, we have;
0.00012 × 9.81 = 000011772 N
Substituting the values, we have;
q = 0.1086 micro Coulombs.