Answer: Context
Explanation: It is always very important for an engineer to keep the context of his/her expirament in mind.
Answer:
The volume percentage of graphite is 10.197 per cent.
Explanation:
The volume percent of graphite is the ratio of the volume occupied by the graphite phase to the volume occupied by the graphite and ferrite phases. The weight percent in the cast iron is 3.2 wt% (graphite) and 96.8 wt% (ferrite). The volume percentage of graphite is:
![\%V_{gr} = \frac{V_{gr}}{V_{gr}+V_{fe}} \times 100\,\%](https://tex.z-dn.net/?f=%5C%25V_%7Bgr%7D%20%3D%20%5Cfrac%7BV_%7Bgr%7D%7D%7BV_%7Bgr%7D%2BV_%7Bfe%7D%7D%20%5Ctimes%20100%5C%2C%5C%25)
Where:
- Volume occupied by the graphite phase, measured in cubic centimeters.
- Volume occupied by the graphite phase, measured in cubic centimeters.
The expression is expanded by using the definition of density and subsequently simplified:
![\%V_{gr} = \frac{\frac{m_{gr}}{\rho_{gr}} }{\frac{m_{gr}}{\rho_{gr}}+\frac{m_{fe}}{\rho_{fe}}}\times 100\,\%](https://tex.z-dn.net/?f=%5C%25V_%7Bgr%7D%20%3D%20%5Cfrac%7B%5Cfrac%7Bm_%7Bgr%7D%7D%7B%5Crho_%7Bgr%7D%7D%20%7D%7B%5Cfrac%7Bm_%7Bgr%7D%7D%7B%5Crho_%7Bgr%7D%7D%2B%5Cfrac%7Bm_%7Bfe%7D%7D%7B%5Crho_%7Bfe%7D%7D%7D%5Ctimes%20100%5C%2C%5C%25)
Where:
,
- Masses of the ferrite and graphite phases, measured in grams.
- Densities of the ferrite and graphite phases, measured in grams per cubic centimeter.
![\%V_{gr} = \frac{1}{1+\frac{\frac{m_{fe}}{\rho_{fe}} }{\frac{m_{gr}}{\rho_{gr}} } }\times 100\,\%](https://tex.z-dn.net/?f=%5C%25V_%7Bgr%7D%20%3D%20%5Cfrac%7B1%7D%7B1%2B%5Cfrac%7B%5Cfrac%7Bm_%7Bfe%7D%7D%7B%5Crho_%7Bfe%7D%7D%20%7D%7B%5Cfrac%7Bm_%7Bgr%7D%7D%7B%5Crho_%7Bgr%7D%7D%20%7D%20%7D%5Ctimes%20100%5C%2C%5C%25)
![\%V_{gr} = \frac{1}{1 + \left(\frac{\rho_{gr}}{\rho_{fe}} \right)\cdot\left(\frac{m_{fe}}{m_{gr}} \right)} \times 100\,\%](https://tex.z-dn.net/?f=%5C%25V_%7Bgr%7D%20%3D%20%5Cfrac%7B1%7D%7B1%20%2B%20%5Cleft%28%5Cfrac%7B%5Crho_%7Bgr%7D%7D%7B%5Crho_%7Bfe%7D%7D%20%5Cright%29%5Ccdot%5Cleft%28%5Cfrac%7Bm_%7Bfe%7D%7D%7Bm_%7Bgr%7D%7D%20%5Cright%29%7D%20%5Ctimes%20100%5C%2C%5C%25)
If
,
,
and
, the volume percentage of graphite is:
![\%V_{gr} = \frac{1}{1+\left(\frac{2.3\,\frac{g}{cm^{3}} }{7.9\,\frac{g}{cm^{3}} } \right)\cdot \left(\frac{96.8\,g}{3.2\,g} \right)} \times 100\,\%](https://tex.z-dn.net/?f=%5C%25V_%7Bgr%7D%20%3D%20%5Cfrac%7B1%7D%7B1%2B%5Cleft%28%5Cfrac%7B2.3%5C%2C%5Cfrac%7Bg%7D%7Bcm%5E%7B3%7D%7D%20%7D%7B7.9%5C%2C%5Cfrac%7Bg%7D%7Bcm%5E%7B3%7D%7D%20%7D%20%5Cright%29%5Ccdot%20%5Cleft%28%5Cfrac%7B96.8%5C%2Cg%7D%7B3.2%5C%2Cg%7D%20%5Cright%29%7D%20%5Ctimes%20100%5C%2C%5C%25)
![\%V_{gr} = 10.197\,\%V](https://tex.z-dn.net/?f=%5C%25V_%7Bgr%7D%20%3D%2010.197%5C%2C%5C%25V)
The volume percentage of graphite is 10.197 per cent.
Answer:
Explanation:
The options are:
- In an isometric drawing, multiple angles and axes can be shown in one sketch.
- There is no room for detail in an isometric drawing, so the detail is shown in the orthographic projection.
- Only one sketch will be needed since all other previous designs will no longer be necessary.
- Computer programs will not be necessary to create the exact dimensions of the design.
Orthographic projections are in either the First or Third Angles but the angles are fixed and do not provide perspective view. Isometric drawings are perspective views from different angles.
So Ethan's skill is valuable because "In an isometric drawing, multiple angles and axes can be shown in one sketch."
Answer: Hello :)
They are in the <u>nutrient pollution</u> category.
Explanation:
Answer: a) 0.948 b) 117.5µf
Explanation:
Given the load, a total of 2.4kw and 0.8pf
V= 120V, 60 Hz
P= 2.4 kw, cos θ= 80
P= S sin θ - (p/cos θ) sin θ
= P tan θ(cos^-1 (0.8)
=2.4 tan(36.87)= 1.8KVAR
S= 2.4 + j1. 8KVA
1 load absorbs 1.5 kW at 0.707 pf lagging
P= 1.5 kW, cos θ= 0.707 and θ=45 degree
Q= Ptan θ= tan 45°
Q=P=1.5kw
S1= 1.5 +1.5j KVA
S1 + S2= S
2.4+j1.8= 1.5+1.5j + S2
S2= 0.9 + 0.3j KVA
S2= 0.949= 18.43 °
Pf= cos(18.43°) = 0.948
b.) pf to 0.9, a capacitor is needed.
Pf = 0.9
Cos θ= 0.9
θ= 25.84 °
(WC) V^2= P (tan θ1 - tan θ2)
C= 2400 ( tan (36. 87°) - tan (25.84°)) /2 πf × 120^2
f=60, π=22/7
C= 117.5µf