Answer:
a. lighting and receptacle outlets
Explanation:
The two types of outlets that are found in an electrical system are
a. lighting and receptacle outlets
Outlets allow electrical equipment to connect to the electrical grid. The electrical grid provides alternating current to the outlet.
 
        
             
        
        
        
Answer:
The three phase full load secondary amperage is 2775.7 A
Explanation:
Following data is given, 
S = Apparent Power = 1000 kVA
No. of phases = 3 
Secondary Voltage: 208 V/120 V <em>(Here 208 V is three phase voltage and 120 V is single phase voltage) </em>
<em>Since,</em>
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The formula for apparent power in three phase system is given as:

Where:
S = Apparent Power
V = Line Voltage
I = Line Current
In order to calculate the Current on Secondary Side, substituting values in above formula,

  
 
        
             
        
        
        
Answer: Pi= 4 - 4/3 + 4/5 - 4/7 + 4/9 ...
Explanation:
Is the same as the example, 
If Π/4 = 1 - 1/3 + 1/5 - 1/7 + 1/9 ...
Then
(Π/4 )*4= 4*(1 - 1/3 + 1/5 - 1/7 + 1/9 ...)
Π =4 - 4/3 + 4/5 - 4/7 + 4/9 ...
The way to write this is 
Sum(from n=0 to n=inf) of (-1)^n 4/(2n+1) 
(photo) 
 
        
             
        
        
        
Answer:
Explanation:
ADT for an 2-D array:
struct array{
int arr[10];
}arrmain[10];
An application that stores an array with 1000 rows and 1000 columns, where less than 10,000 of the array values are non-zero. The two different implementations for such arrays that would be more space efficient than a standard two-dimensional array implementation requiring one million positions are :
1) struct array{
int *p;
}arr[1000];
2) struct array{
int *p;
}arr[1000];
 
        
             
        
        
        
Answer:
fluid nozzle that is too large