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Vika [28.1K]
3 years ago
9

an oven adds 2260 j heat to a zinc tray that weighs 195g of the tray starts at 25 what is the final temperature of the tray

Chemistry
2 answers:
inessss [21]3 years ago
7 0

Answer:  Assuming 25 is 25C, 54.9C

Explanation:  The specific heat of zinc is 0.388 J/gC.  With 195 grams, we see that for the whole tray, the temperature will change by 1 C for every 75.66J, since (0.388J/gC)*(195g) = 75.66 J/C.

Thus, (2260J)/(75.66J/C) = 29.9 C increase.  Add that to 25 to yield 54.9 C (or K, if the 25 was in Kelvin).

choli [55]3 years ago
5 0
Divide the grams by 25 to 195 then times it in decimal
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Explanation:

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3 years ago
A gas has a pressure of 1.34 atm when the temperature is 237K. The gas is then heated until the temperature measures 312K. What
alexandr1967 [171]

The answer for the following question is answered below.

  • <em><u>Therefore the new pressure of the gas is 1.76 atm.</u></em>

Explanation:

Given:

Initial pressure of the gas = 1.34 atm

Initial temperature of the gas = 273 K

final temperature of the gas = 312 K

To solve:

Final temperature of the gas

We know;

From the ideal gas equation

P × V = n × R × T

So;

from the above equation we can say that

    <em>P ∝ T</em>

     \frac{P}{T} = constant  

     \frac{P_{1} }{P_{2} } = \frac{T_{1} }{T_{2} }

Where;

P_{1} = initial pressure of a gas

P_{2} = final pressure of a gas

T_{1} = initial temperature of a gas

T_{2} = final temperature of  a gas

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6 0
3 years ago
What is a valence electron and why are they so important to a chemist?
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3 0
3 years ago
An air compressor takes atmospheric air (think about what pressure it is at) and pressures it up to 68 (psig). In the process, i
Aleks [24]

Answer:

5.19 m³  

Explanation:

Data Given:

initial Pressure P1 = atmospheric pressure

Reported atmospheric pressure =  14.696 psi

Final pressures P2 =  68 psi

initial Temperature T1 =  26 °C

final Temperature T2 =  48 °C

initial Volume V1= 13 m³

final Volume V2 = ?

Solution:

Formula will be used

                    P1 V1 / T1 = P2 V2 / T2

To calculate volume rearrange the above formula

                   V2 = (P1 V1) T2 / T1 P2 . . . . . . . .(1)

put values in equation 1

                  V2 = (14.696 psi x 13 m³) 48 °C / 26 °C x 68 psi

                  V2 = (191.05 psi m³) 48 °C / 1768 °C psi

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                  V2 = 5.19 m³

So, final volume is 5.19 m³                

7 0
3 years ago
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