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3 years ago

an oven adds 2260 j heat to a zinc tray that weighs 195g of the tray starts at 25 what is the final temperature of the tray

Chemistry

2 answers:

inessss [21]3 years ago

7 0

Answer: Assuming 25 is 25C, 54.9C

Explanation: The specific heat of zinc is 0.388 J/gC. With 195 grams, we see that for the whole tray, the temperature will change by 1 C for every 75.66J, since (0.388J/gC)*(195g) = 75.66 J/C.

Thus, (2260J)/(75.66J/C) = 29.9 C increase. Add that to 25 to yield 54.9 C (or K, if the 25 was in Kelvin).

choli [55]3 years ago

5 0

Divide the grams by 25 to 195 then times it in decimal

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$CO(g)+H_2O(g)\rightleftharpoons CO_2(g)+H_2(g)$

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