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3 years ago

Create a sentence about a cat for each type of figurative language

2 answers:

meriva3 years ago

5 0

1.) Onomatopoeia - The use of words whose sounds suggest their meanings.

Meow purred the cat as I scratched behind it's ear.

2.) Personification - A figure of speech in which human qualities are attributed to an object, animal or idea.

The cat rolled it's eyes at it's humans obnoxious behaviour.

3.) Alliteration - The repetition of sounds/letters at the beginning of a word.

The keeper couldn’t keep all the cats in their cages.

4.) Pun - A play on words.

You have cat to be kitten me right now!

5.) Hyperbole - An over-exaggeration.

The cat jumped so high I swore it was going to the moon!

6.) Idiom - A figurative meaning of the connotation of the word. (Different from the literal meaning.)

Well, she sure is another breed of cat, I'll tell you that!

(omg it rhymes too how exciting !!)

7.) Simile - A comparison using like or as.

The cat's fur was as dark as night.

8.) Metaphor - A comparison not using like or as.

The cat's fur was a blanket of warmth!!

Hope these examples helped !! :-)

Elza [17]3 years ago

5 0

Explanation:

Simile: it describes something comparing it to something else. It usually uses the words like or as. "That cat is as big as a panther!"
Metaphor: it describes a subject or action figuratively by making a comparison. "That cat is a panther"
Hyperbole: is the exaggeration of ideas in order to make an emphasis. "That cat is bigger than a panther!"
Personification: is when you give human atributes to an idea or animal. "That cat prances like a beauty queen"
Allitration: occurs when words that have the same first consonant sound, are close together. "Calmly having a catnap, the cat is c lawing at the curtains"

I hope you find this information useful and interesting! Good luck!

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a 20.5g sample of cleaning detergent contains 8.61g of NH40H.CALCULATE the percentage composition of nitrogen in the cleaning de

AysviL [449]

Answer:

The mass percentage composition of nitrogen in the sample of the cleaning detergent is approximately 16.78%

Explanation:

The given mass of the sample of the cleaning detergent, m₁ = 20.5 g

The mass of the ammonium hydroxide, NH₄OH in the detergent, m₂ = 8.61 g

The molar mass of NH₄OH = 35.04 g/mol

The molar mass of nitrogen, N = 14.01 g/mol

Therefore, the mass, m₃ of nitrogen, N, in 8.61 g of ammonium hydroxide, NH₄OH, is found as follows;

m₃ = (14.01/35.04) × 8.61 g = (402,087/118,800) g ≈ 3.44 g

The mass of nitrogen, N, in the ammonium hydroxide, NH₄OH, contained in the 20.5 g sample of the cleaning agent, m₃ ≈ 3.44 grams

The percentage composition of nitrogen in the sample of the cleaning detergent, %N is given as follows;

$\% Composition = \dfrac{Mass \ of \ component}{Total \ mass \ of \ cleaning \ detergent} \times 100$

Therefore;

%N ≈ ((3.44 g)/(20.5 g)) × 100 ≈ 16.78 %

The percentage composition of nitrogen, %N ≈ 16.78%.

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3 years ago

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Marysya12 [62]

Answer:

crushing an ice cube

Explanation:

crushing an ice cube can be redone by freezing it again in its position

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2 years ago

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Answer:

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3 years ago

Distillation is used to separate _____.

Art [367]

Distillation is the process of separating homogeneous mixtures -and a solution is a homogenous mixture, so this is the correct answer!

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3 years ago

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There are two binary compounds of mercury and oxygen. heating either of them results in the decomposition of the compound, with

grandymaker [24]

$\text{Hg} \text{O}$ and $\text{Hg}_{2} \text{O}$ .

Assuming complete decomposition of both samples,

$m(\text{Hg}) = m(\text{residure})$
$m(\text{O}) = m(\text{loss})$

First compound:

$m(\text{O}) = m(\text{loss}) = 0.6498 - 0.6018 = 0.048 \; g$
$m(\text{Hg}) = m(\text{residure}) = 0.6018 \; g$

$n = m/M$ ; $0.6498 \; g$ of the first compound would contain

$n(\text{O atoms}) = 0.048 \; g / 16 \; g \cdot mol^{-1}= 0.003 \; mol$
$n(\text{Hg atoms}) = 0.6018 \; g / 200.58 \; g \cdot mol^{-1}= 0.003 \; mol$

Oxygen and mercury atoms seemingly exist in the first compound at a $1:1$ ratio; thus the empirical formula for this compound would be $\text{Hg} \text{O}$ where the subscript "1" is omitted.