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kvasek [131]
3 years ago
12

A shipping box in the shape of a cube has an edge length of 8 inches. It can hold 8 mugs with no extra space between them.

Mathematics
2 answers:
erik [133]3 years ago
6 0
The  bigger box will have a volume 2^3 greater than the smaller box. That is  8 times larger.

So number of mugs it can hold is 8*8  = 64 mugs.
BabaBlast [244]3 years ago
3 0

Answer: The box can hold up to 64 mugs

Step-by-step explanation:

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Fezzik, the giant is berated by Vizzini, who says he is nothing more than a “landmass.” What evidence shows you that Vizzini is
brilliants [131]

Answer:

What evidence shows you that Vizzini is wrong, that Fezzik has ... Fezzik, the giant is berated by Vizzini, who says he is nothing more than a “landmass. ... wrong, that Fezzik has value that extends beyond his large physique?

Step-by-step explanation:

5 0
2 years ago
Please answer this question
Alina [70]

Answer:

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12 x 4 x 7 + 1

__

Step-by-step explanation:

The biggest number can be made by multiplying all the numbers. However, since one of these numbers is 1, multiplying 1 by all those others won’t do anything. So to get the biggest number you would multiply 12 by 4 by 7 and add 1.

3 0
2 years ago
Simplify the expression. A) 8^4•8^9
OlgaM077 [116]

Answer:

{8}^{13}

Step-by-step explanation:

{8}^{4}  \times  {8}^{9}  \\  {8}^{4 + 9}  \\  {8}^{13}  \\  = 5.497558139 \times 10 ^{11}

Hope this helps you.

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7 0
3 years ago
Xyz are in 3:3:6.what are the measures of the angles
Anni [7]
Answer:

Set up an equation equal to <span>180o</span>

Explanation:

<span>3x+3x+6x=180</span>

<span>12x=180</span>

<span>x=<span>18012</span>=15</span>

So, the measure of the angles are:

<span>3x=3×15=45</span>
<span>3x=3×15=45</span>
<span>6x=6×15=<span>90</span></span>

6 0
3 years ago
Use Fermat's Little Theorem to determine 7^542 mod 13.
m_a_m_a [10]

a^{p-1} \equiv 1 \pmod p where p is prime, a\in\mathbb{Z} and a is not divisible by p.

7^{13-1}\equiv 1 \pmod {13}\\7^{12}\equiv 1 \pmod {13}\\\\542=45\cdot12+2\\\\7^{45\cdot 12}\equiv 1 \pmod {13}\\7^{45\cdot 12+2}\equiv 7^2 \pmod {13}\\7^{542}\equiv 49 \pmod{13}

4 0
3 years ago
Read 2 more answers
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