2x2−5x=3
I think the first step would be to
Subtract 3 from both sides
2x2−5x−3=3−3
2x2−5x−3=0
Then
For this equation: a=2, b=-5, c=-3
2x2+−5x+−3=0
Lastly you would
Use quadratic formula with a=2, b=-5, c=-3
I think your answer would then have to be...
x = 3 or x = −1
/2
.7 repeating would make it 7/9
X + 5 + 11x = 12x + y
Simplify: 12x + 5 = 12x + y (We are adding x and 11x on the left side)
Subtract 12x from each side makes each zero.
5 = y
So we can plug in and test. I'm picking two random numbers to plug in for x. 10, and 82
x = 10, y = 5
10 + 5 + 11(10) = 12(10) + 5
125 = 125
x = 82, y = 5
82 + 5 + 11(82) = 12(82) + 5
989 = 989
So we verified y = 5
