1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
DENIUS [597]
3 years ago
9

Mika read a 405 page book in 6 hours. how many pages per minute did she read?

Mathematics
1 answer:
Annette [7]3 years ago
5 0

Answer:

1.125 pages per minute

Step-by-step explanation:

Mika read a 405 page book in 6 hours.

6 hours is equivalent to

6 × 60 minutes = 360 minutes

Number of pages read per minute = 405/360

                                                         = 9/8 = 1.125 pages

Mika read 1.125 pages per minute.

You might be interested in
40 pounds of dog food cost $50 how much would 35 pounds of dog food cost
astraxan [27]
50:40=x:35
5/4=x/35
times both sides by (4*35)
5*35=4x
175=4x
divide both sides by 4
43.75=x

costs $43.75
3 0
3 years ago
How do you answer this MATH
raketka [301]
X = 5 or x = 13.

If you need details, please ask!
7 0
3 years ago
Read 2 more answers
Qhat is 3 groupps of 1/8
iragen [17]

Answer: 3/8ths

Step-by-step explanation: 1/8+1/8+1/8=3/8

4 0
2 years ago
Which of the following expressions could be used to estimate the difference between -12.34 and -4.8? -12 - 5 -12 + 5 -12 - 4 -12
Sphinxa [80]
This is your answer

<span>-12 - 5 (first one)

hope that helps

</span>
5 0
3 years ago
Read 2 more answers
Let X and Y be discrete random variables. Let E[X] and var[X] be the expected value and variance, respectively, of a random vari
Ulleksa [173]

Answer:

(a)E[X+Y]=E[X]+E[Y]

(b)Var(X+Y)=Var(X)+Var(Y)

Step-by-step explanation:

Let X and Y be discrete random variables and E(X) and Var(X) are the Expected Values and Variance of X respectively.

(a)We want to show that E[X + Y ] = E[X] + E[Y ].

When we have two random variables instead of one, we consider their joint distribution function.

For a function f(X,Y) of discrete variables X and Y, we can define

E[f(X,Y)]=\sum_{x,y}f(x,y)\cdot P(X=x, Y=y).

Since f(X,Y)=X+Y

E[X+Y]=\sum_{x,y}(x+y)P(X=x,Y=y)\\=\sum_{x,y}xP(X=x,Y=y)+\sum_{x,y}yP(X=x,Y=y).

Let us look at the first of these sums.

\sum_{x,y}xP(X=x,Y=y)\\=\sum_{x}x\sum_{y}P(X=x,Y=y)\\\text{Taking Marginal distribution of x}\\=\sum_{x}xP(X=x)=E[X].

Similarly,

\sum_{x,y}yP(X=x,Y=y)\\=\sum_{y}y\sum_{x}P(X=x,Y=y)\\\text{Taking Marginal distribution of y}\\=\sum_{y}yP(Y=y)=E[Y].

Combining these two gives the formula:

\sum_{x,y}xP(X=x,Y=y)+\sum_{x,y}yP(X=x,Y=y) =E(X)+E(Y)

Therefore:

E[X+Y]=E[X]+E[Y] \text{  as required.}

(b)We  want to show that if X and Y are independent random variables, then:

Var(X+Y)=Var(X)+Var(Y)

By definition of Variance, we have that:

Var(X+Y)=E(X+Y-E[X+Y]^2)

=E[(X-\mu_X  +Y- \mu_Y)^2]\\=E[(X-\mu_X)^2  +(Y- \mu_Y)^2+2(X-\mu_X)(Y- \mu_Y)]\\$Since we have shown that expectation is linear$\\=E(X-\mu_X)^2  +E(Y- \mu_Y)^2+2E(X-\mu_X)(Y- \mu_Y)]\\=E[(X-E(X)]^2  +E[Y- E(Y)]^2+2Cov (X,Y)

Since X and Y are independent, Cov(X,Y)=0

=Var(X)+Var(Y)

Therefore as required:

Var(X+Y)=Var(X)+Var(Y)

7 0
3 years ago
Other questions:
  • 5. Twenty-five sixth-grade students entered a math contest consisting of 20 questions. The student who
    14·1 answer
  • In parallelogram MATH m
    12·1 answer
  • The sum of b and 9 is 12 less than 20
    5·1 answer
  • Describe each sequence using words and symbols 25,50,75,......
    14·1 answer
  • Is 3 Kl bigger or 3000 L
    14·1 answer
  • Please help
    10·1 answer
  • Helppppp pleasseeeee
    10·1 answer
  • Someone plz help me plz
    15·2 answers
  • answer plsss answer plss
    10·1 answer
  • Given:
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!