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Julli [10]
3 years ago
12

Please everyone do this and send me​

Chemistry
1 answer:
Akimi4 [234]3 years ago
7 0

Answer: question 2 is (a) (25+273)k=298k(b) (373+273)k=646k

question 5 is 25 degree Celsius

question 1 is

a = (293-273) =20 degree Celsius

b = (470-273)=197 degree Celsius

question 3 is

a = naphthalene ball undergo sublimation due to which it convert directly into vapour and disappear into air without leaving any solid

b = the participle of perfume diffuse rapidly into air and its smell can be felt while sitting serval metre away

question 4 isthe force of allraction between the particles increases as we go from liquid to gas so the required order is : Oxygen< water< sugar

I hope it is helpful to you

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Why are most organic compounds nonconducting and insoluble in water?
maksim [4K]
I think the correct answers from the choices listed above are the second and the last options. Organic compounds are nonducting and insoluble in water because of the bonds that these compounds contain. Most organic compounds don't dissolve in water because they are nonpolar. They don't conduct electricity because they are covalent, not ionic.
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The scale most widely used by scientist for measuring earth quakes is called what
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Does the temperature of the solvent (water) affect the rate of dissolving?​
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3 0
3 years ago
The lab just ran out of 1 M HCl that you need to complete the Benzillic Acid lab. The TA tells you there is 12 M HCl in the fume
Viktor [21]

Answer:

0.83 mL

Explanation:

Given data

  • Initial concentration (C₁): 12 M
  • Initial volume (V₁): ?
  • Final concentration (C₂): 1.0 M
  • Final volume (V₂): 10.0 mL

We can calculate the initial volume of HCl using the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 1.0 M × 10.0 mL / 12 M

V₁ = 0.83 mL

The required volume of the initial solution is 0.83 mL.

7 0
3 years ago
Please help me with this chemistry problem
Margarita [4]

Answer:

50 g of K₂CO₃ are needed

Explanation:

How many grams of K₂CO₃ are needed to make 500 g of a 10% m/m solution?

We analyse data:

500 g is the mass of the solution we want

10% m/m is a sort of concentration,  in this case means that 10 g of solute (K₂CO₃) are contained in 100 g of solution

Therefore we can solve this, by a rule of three:

In 100 g of solution we have 10 g of K₂CO₃

In 500 g of solution we may have, (500 . 10) / 100 = 50 g of K₂CO₃

6 0
3 years ago
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