Answer:
a. Remaining at rest requires the use of ATP.
Explanation:
The resting membrane potential is maintained by the sodium-potassium pump. The sodium potassium pump does this by actively pumping sodium ions out of the cell and potassium ions inside the cell in a ratio of 3:2. This movement of ions by the sodium-potassium pump is against their concentration gradient. In a neuron at rest, there are more sodium ions outside the cell than there are inside the cell. Also, there are are more potassium ions inside the cell than there are outside the cell. However, there are ion channels through which these ions enter and leave the cell. Sodium ion channels allow sodium to enter the cell following its concentration gradient, whereas, potassium ion channels allow potassium to leave the cell following its concentration gradient. However, more potassium ions leave the cell than do sodium ions enter the cell because of the higher permeability of the cell to potassium ions.
In order to maintain the resting membrane potential, the sodium potassium pump powered by the hydrolysis of an ATP molecules pumps sodium ions out of the cell and potassium ions into the cell.
<em>Therefore, the correct option is A, as ATP is needed by the sodium-potassium pump in order to maintain the resting membrane potential.</em>
Answer:
proton and electrons orbit close together around a center nucleus
Answer:
Mx will be less than My.
Explanation:
The correct option is - Mx will be less than My.
Because, liquid X have been higher viscosity and vapor pressure than liquid B.
Vapor pressure of liquid A is greater, so the amount of liquid X will vaporized greater and H2 gas has been displaced greater from the beaker as compared to liquid Y.
The amount of H2 in liquid Y remains greater in beaker as compared to liquid X.
So, Mx will be less than My.
<span>[Ag+]3[PO4]3-
Ag3PO4(aq) ----> 3Ag^+(aq) + PO4^3-(aq)
In pure water, the molarity of PO4^3-, which is 1.76x10^-5 M, also represents the molar solubility of Ag3PO4, that means that max 1.76x10^-5 mol Ag3PO4 dissolves in 1L (1000 mL) of water. When the amount of water is halved to 500 mL, the solubility of Ag3PO4 is also halved. (8.8x10^-5 mol).
Ag3PO4(aq) ----> 3Ag^+(aq) + PO4^3-(aq)
8.8x10^-5 mol ..... 3x8.8x10^-5 mol = 2.64x10^-4 mol
[Ag^+] = n / V = 2.64x10^-4 mol / 0.500 L = 5.28x10^-4 M</span>
