Answer:
#include <stdio.h>
void SplitIntoTensOnes(int* tensDigit, int* onesDigit, int DecVal){
*tensDigit = (DecVal / 10) % 10;
*onesDigit = DecVal % 10;
return;
}
int main(void) {
int tensPlace = 0;
int onesPlace = 0;
int userInt = 0;
userInt = 41;
SplitIntoTensOnes(&tensPlace, &onesPlace, userInt);
printf("tensPlace = %d, onesPlace = %d\n", tensPlace, onesPlace);
return 0;
}
Answer:
Step 1: State your null and alternate hypothesis. ...
Step 2: Collect data. ...
Step 3: Perform a statistical test. ...
Step 4: Decide whether the null hypothesis is supported or refuted. ...
Step 5: Present your findings.
Answer:
The Answer to the question is :
Explanation:
The contact angle between the mercury surface and capillary tube wall is Greater than 90.
If the surface of the solid is hydrophobic, the contact angle will be greater than 90 °. On very hydrophobic surfaces the angle can be greater than 150º and even close to 180º.
Answer:
Explanation:
We need to calculate the change in storage through the changes given,
That is,
Where the loss are representing by,
So calculating the values we have
The values inside the are parenthesis need to be konverted as I note here.
That is,
Answer:
Iin(t) =1.3 × (-0.8/1.56) e^-t/1.56 A
Explanation:
In physics, the determination of the term " natural response" simply means that we want to know what happens in a circuit when the value of t = 0, that is to say after the circuit has been disconnected. Hence, the value of the voltage and the current can then be determined or Calculated;
For the the natural response of i in(t) we will be using the formula below;
I(t) = Vo × t/ R = Vo/R × e^-t/h.
Where h = 1/RC = time constant.
For t= 0^- = 0.8 × 1= 0.8 V.
1/Ctotal = 1/ 2 + 1/3 = 6/5
For t = 0^+;
h =( 0.8 + 0.5) × 6/5 = 1.56 seconds.
Hence, we will have;
Vin(t) = 0.8 × e^-t/1.56.
Iin(t) =1.3 × (-0.8/1.56) e^-t/1.56
