Answer:
abrir candados y abrir puertas
Explanation:
Answer:
Thank you for this!
Explanation:
I was about to click it on a question I saw.
Answer:
The temperature of the strip as it exits the furnace is 819.15 °C
Explanation:
The characteristic length of the strip is given by;
![L_c = \frac{V}{A} = \frac{LA}{2A} = \frac{5*10^{-3}}{2} = 0.0025 \ m](https://tex.z-dn.net/?f=L_c%20%3D%20%5Cfrac%7BV%7D%7BA%7D%20%3D%20%5Cfrac%7BLA%7D%7B2A%7D%20%3D%20%5Cfrac%7B5%2A10%5E%7B-3%7D%7D%7B2%7D%20%3D%200.0025%20%5C%20m)
The Biot number is given as;
![B_i = \frac{h L_c}{k}\\\\B_i = \frac{80*0.0025}{21} \\\\B_i = 0.00952](https://tex.z-dn.net/?f=B_i%20%3D%20%5Cfrac%7Bh%20L_c%7D%7Bk%7D%5C%5C%5C%5CB_i%20%3D%20%5Cfrac%7B80%2A0.0025%7D%7B21%7D%20%5C%5C%5C%5CB_i%20%3D%200.00952)
< 0.1, thus apply lumped system approximation to determine the constant time for the process;
![\tau = \frac{\rho C_p V}{hA_s} = \frac{\rho C_p L_c}{h}\\\\\tau = \frac{8000* 570* 0.0025}{80}\\\\\tau = 142.5 s](https://tex.z-dn.net/?f=%5Ctau%20%3D%20%5Cfrac%7B%5Crho%20C_p%20V%7D%7BhA_s%7D%20%3D%20%5Cfrac%7B%5Crho%20C_p%20L_c%7D%7Bh%7D%5C%5C%5C%5C%5Ctau%20%3D%20%5Cfrac%7B8000%2A%20570%2A%200.0025%7D%7B80%7D%5C%5C%5C%5C%5Ctau%20%3D%20142.5%20s)
The time for the heating process is given as;
![t = \frac{d}{V} \\\\t = \frac{3 \ m}{0.01 \ m/s} = 300 s](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7Bd%7D%7BV%7D%20%5C%5C%5C%5Ct%20%3D%20%5Cfrac%7B3%20%5C%20m%7D%7B0.01%20%5C%20m%2Fs%7D%20%3D%20300%20s)
Apply the lumped system approximation relation to determine the temperature of the strip as it exits the furnace;
![T(t) = T_{ \infty} + (T_i -T_{\infty})e^{-t/ \tau}\\\\T(t) = 930 + (20 -930)e^{-300/ 142.5}\\\\T(t) = 930 + (-110.85)\\\\T_{(t)} = 819.15 \ ^0 C](https://tex.z-dn.net/?f=T%28t%29%20%3D%20T_%7B%20%5Cinfty%7D%20%2B%20%28T_i%20-T_%7B%5Cinfty%7D%29e%5E%7B-t%2F%20%5Ctau%7D%5C%5C%5C%5CT%28t%29%20%3D%20930%20%2B%20%2820%20-930%29e%5E%7B-300%2F%20142.5%7D%5C%5C%5C%5CT%28t%29%20%3D%20930%20%2B%20%28-110.85%29%5C%5C%5C%5CT_%7B%28t%29%7D%20%3D%20819.15%20%5C%20%5E0%20C)
Therefore, the temperature of the strip as it exits the furnace is 819.15 °C
Answer:
Check the explanation
Explanation:
The loop invariant has to satisfy some amount of requirements to be of good use. Another complex factor as to why a loop is the question of loop termination. A loop that doesn’t terminate can’t invariably be correct, and in fact the computation in whatever form amounts to nothing. The total axiomatic description of a while construct will have to involve all of the following to be true, in which I is the loop invariant:
P => I
{I and B} S {I}
(I and (not B)) => Q
Then the loop terminates
Answer:
The critical length of surface flaw = 6.176 mm
Explanation:
Given data-
Plane strain fracture toughness Kc = 29.6 MPa-m1/2
Yield Strength = 545 MPa
Design stress. =0.3 × yield strength
= 0.3 × 545
= 163.5 MPa
Dimensionless parameter. Y = 1.3
The critical length of surface flaw is given by
= 1/pi.(Plane strain fracture toughness /Dimensionless parameter× Design Stress)^2
Now putting values in above equation we get,
= 1/3.14( 29.6 / 1.3 × 163.5)^2
=6.176 × 10^-3 m
=6.176 mm