153.888 grams are in 4.8 moles of sulfur
Answer:
A. Any substance with a pH above 7.
Explanation:
On the pH scale substances whose value is greater than 7 and less than 14 are termed alkali.
Acids have a pH of less than 7 whereas neutral compounds such as water has pH of 7.
- An alkali is any substance that produces excess hydroxyl ion in solutions.
- Water soluble bases are known as alkali.
- They are usually certain metallic oxides, metallic hydroxides and aqueous ammonia.
Leftover: approximately 11.73 g of sulfuric acid.
<h3>Explanation</h3>
Which reactant is <em>in excess</em>?
The theoretical yield of water from Al(OH)₃ is lower than that from H₂SO₄. As a result,
- Al(OH)₃ is the limiting reactant.
- H₂SO₄ is in excess.
How many <em>moles</em> of H₂SO₄ is consumed?
Balanced equation:
2 Al(OH)₃ + 3 H₂SO₄ → Al₂(SO₄)₃ + 6 H₂O
Each mole of Al(OH)₃ corresponds to 3/2 moles of H₂SO4. The formula mass of Al(OH)₃ is 78.003 g/mol. There are 15 / 78.003 = 0.19230 moles of Al(OH)₃ in the five grams of Al(OH)₃ available. Al(OH)₃ is in excess, meaning that all 0.19230 moles will be consumed. Accordingly, 0.19230 × 3/2 = 0.28845 moles of H₂SO₄ will be consumed.
How many <em>grams</em> of H₂SO₄ is consumed?
The molar mass of H₂SO₄ is 98.076 g.mol. The mass of 0.28845 moles of H₂SO₄ is 0.28845 × 98.076 = 28.289 g.
How many <em>grams</em> of H₂SO₄ is in excess?
40 grams of sulfuric acid H₂SO₄ is available. 28.289 grams is consumed. The remaining 40 - 28.289 = 11.711 g is in excess. That's closest to the first option: 11.73 g of sulfuric acid.
Advantages
less wasted energy
Reduces fossilisation
Disadvantages
- Expensive
- doesn't look nice ( apparently)
Answer is: the molarity of a solution of HF is 0.73 M.
n(HF) = 4.400 mol; amount of hydrofluoric acid.
V(HF) = 6.00 l; volume of hydrofluoric acid.
c(HF) = n(HF) ÷ V(HF).
c(HF) = 4.400 mol ÷ 6.00 l.
c(HF) = 0.733 mol/l; molarity of a solution (hydrofluoric acid).
