So is doubling, first off, meaning, if the current amount say P, then when it doubles is 2P, or double that, or P + P, so the rate of growth is 100%, since it's doubling.
and is doing it every 9 hour cycle, thus
![\bf \textit{Periodic/Cyclical Exponential Growth}\\\\ A=P(1 + r)^{\frac{t}{c}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\to &650\\ r=rate\to 100\%\to \frac{100}{100}\to &1.00\\ t=\textit{elapsed time}\to &10\\ c=period\to &9 \end{cases} \\\\\\ A=650(1 + 1)^{\frac{10}{9}}\implies A=650(2)^{\frac{10}{9}}\implies A=650\sqrt[9]{2^{10}}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7BPeriodic%2FCyclical%20Exponential%20Growth%7D%5C%5C%5C%5C%0AA%3DP%281%20%2B%20r%29%5E%7B%5Cfrac%7Bt%7D%7Bc%7D%7D%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0AA%3D%5Ctextit%7Baccumulated%20amount%7D%5C%5C%0AP%3D%5Ctextit%7Binitial%20amount%7D%5Cto%20%26650%5C%5C%0Ar%3Drate%5Cto%20100%5C%25%5Cto%20%5Cfrac%7B100%7D%7B100%7D%5Cto%20%261.00%5C%5C%0At%3D%5Ctextit%7Belapsed%20time%7D%5Cto%20%2610%5C%5C%0Ac%3Dperiod%5Cto%20%269%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0AA%3D650%281%20%2B%201%29%5E%7B%5Cfrac%7B10%7D%7B9%7D%7D%5Cimplies%20A%3D650%282%29%5E%7B%5Cfrac%7B10%7D%7B9%7D%7D%5Cimplies%20A%3D650%5Csqrt%5B9%5D%7B2%5E%7B10%7D%7D)
Answer:
29
Step-by-step explanation:
In parallel lines, allied angles have a sum of 180.
Therefore, angle CBD + angle EAB = 180
Therefore, 42 + 109 + x = 180
x + 151 = 180
x = 29
Hope it helps and if it does, please mark me brainliest...
Answer:
2x⁴ + 4x³ + x² + 8x - 6
Step-by-step explanation:
(2x² + 4x - 3)(x² + 2)
2(x² + 2) · x² + 4x(x² + 2) - 3(x² + 2)
2x⁴ + 4x² + 4x(x² + 2) - 3(x² + 2)
2x⁴ + 4x² + 4x³ + 8x - 3x² - 6
2x⁴ + x² + 4x³ + 8x - 6
2x⁴ + 4x³ + x² + 8x - 6
C= 45
All interior angles of a triangle add to 180. 90+45=135. 180-35=45
a= 45
The top angle of the triangle and a make 90 degrees together. 90-45=45
b= 135
Angle a and b together make 180 (they are supplementary). 180-45=135
Increment = 6% = 0.06
The explicit formula for the series is;
C(n) = C(n-1)(1.06), where n = nth month, C(n-1) = cost during previous month, C(n) = cost in month n
Applying the explicit formula;
Current cost = $150
2nd month cost = 150*1.06 = $159
3rd month cost = 159*1.06 = $168.54
The second option is correct.
