<h2><u>
k = 35</u></h2>
Let's solve your equation step-by-step.
14=k(0.4)
Step 1: Simplify both sides of the equation.
14=0.4k
Step 2: Flip the equation.
0.4k=14
Step 3: Divide both sides by 0.4.
= 
<h3><u>
k=35</u></h3>
<span><span>The answer to the question is:</span></span>
<span><span /></span><span><span>−<span>12</span><span>(x−12)</span></span>
</span>
Answer:
x = -5, x = -6
Step-by-step explanation:
After canceling common terms from numerator and denominator, there are two factors remaining in the denominator that can become zero. The vertical asymptotes are at those values of x.
The denominator will be zero when ...
x + 5 = 0 . . . . at x = -5
x + 6 = 0 . . . . at x = -6
H = 16 cm
s = 16.0702 cm
a = 3 cm
e = 16.14 cm
r = 1.5 cm
V = 48 cm3
L = 96.421 cm2
B = 9 cm2
A = 105.421 cm<span>2
The volume of a square pyramid:V = (1/3)a2hSlant Height of a square pyramid:By the Pythagorean theorem, we know thats2 = r2 + h2since r = a/2s2 = (1/4)a2 + h2, ands = √(h2 + (1/4)a2)This is also the height of a triangle sideLateral Surface Area of a square pyramid (4 isosceles triangles):For the isosceles triangle Area = (1/2)Base x Height. Our base is side length a, and for this calculation our height for the triangle is slant height s. With four
sides we need to multiply by 4.L = 4 x (1/2)as = 2as = 2a√(h2 + (1/4)a2)Squaring the 2 to get it back inside the radical,L = a√(a2 + 4h2)Base Surface Area of a square pyramid (square):B = a2Total Surface Area of a square pyramid:A = L + B = a2 + a√(a2 + 4h2))A = a(a + √(a2 + 4h2))</span>
