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3 years ago

Which option is an example of a chemical property?

Chemistry

2 answers:

saveliy_v [14]3 years ago

5 0

<h3>Answer </h3>

Option B= flammability

<h3>Explanation </h3>

Flammability is a chemical property because combustion is a chemical change. A chemical change is a process in which one or more substances are converted into one or more new substances with different properties.

Gasoline is highly flammable. When it burns, it is converted into carbon dioxide and water. These have different properties from gasoline, so combustion is a chemical process. Flammability is a measure of how easily something will burn.

<h3>Examples of chemical properties are: </h3>

Heat of combustion, reactivity with water, PH, and electromotive force.

While density color and melting point are examples of physical properties.

Delvig [45]3 years ago

4 0

Yes, the correct answer is b

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A mixture of 5L of H2 and 3L O2 reacts to form H2O (g) at constant T and P .Find the

slamgirl [31]

The volume of H₂O = 5 L

<h3>Further explanation</h3>

Given

5L of H₂ and 3L O₂

Reaction

2H₂ (g) + O₂(g) ⇒2H₂O(g)

Required

The volume of H₂O

Solution

Avogadro's hypothesis:

In the same T,P and V, the gas contains the same number of molecules

So the ratio of gas volume will be equal to the ratio of gas moles

mol H₂ = 5, mol O₂ = 3

Find limiting reactants

From equation, mol ratio H₂ : O₂ = 2 : 1, so :

$\tt H_2\div O_2=\dfrac{mol~H_2}{coefficient}\div \dfrac{mol~O_2}{coefficient}\\\\=\dfrac{5}{2}\div \dfrac{3}{1}=2.5\div 3\rightarrow H_2~limiting~reactant(smaller~ratio)$

Find volume H₂O

mol H₂O based on mol H₂, and from equation mol ratio H₂ : H₂O=2 : 2, so mol H₂O = 5 mol and the volume also 5 L

4 0

3 years ago

Select the equations below that represent physical changes.

Ierofanga [76]

Physical changes- any change in the physical properties of the substance is a physical change. Generally physical properties include color, state, size , shape, odour, appearance . In any phyical change, no new substance is formed.

Chemical changes- any change in the chemical properties of the substance is a chemical change. Chemical properties changes only when something new is formed during a reaction.

∴ Part A- 2 H2O(l) → 2 H2(g) + O2(g)

In this, H2 and O2 is produced during the reaction which is different from H20. Thus, it is a chemical change.

Part B- H2O(l) → H2O(s)

In this, only the state of water changes from liquid to solid and no new product is formed. Thus, it is a physical change.

Part C-CO2(s) → CO2(g)

In this also, only the state of CO2 changes from solid to gas and no new product is formed. Thus, it is a physical change.

Part D-H2(g) → 2 H(g)

In this reaction, H2 molecule is dissociated into 2 hydrogen atom leading to formation of new products. Thus, it is a chemical change.

Finally, equations that represent physical changes are - B and C

B. H2O(l) → H2O(s)

C. CO2(s) → CO2(g)

6 0

3 years ago

Give the IUPAC name for the following structure: 3-chloro-6-methylcyclohexanol 2-methyl-5-chlorocyclohexanol 1-chloro-4-methylcy

Shtirlitz [24]

Answer:

5-chloro-2-methylcyclohexanol

Explanation:

There is no structure for the compound, but we can analyze the proposed options using the IUPAC rules to name organic compounds.

IUPAC rules state that to name an organic compound, first we have to identify the priorities for the functional groups present in the compound. In this case, the priority functional group is the alcohol group, so we will start the counting of the carbons in this group. Then, the counting of carbon atoms is followed by the next substituents so they have the lowest possible numbers, in this case, we can assign the number 2 to the methyl group and 5 to the chloride group, and name the compound in alphabetical order, using commas to separate the words from the numbers and with no space between the words.

Since the other options involve: high countings for the susbtituents groups (3-chloro-6-methylcyclohexanol), wrong assignation of priority functional group (1-chloro-4-methylcyclohexanol), wrong sequence of counting in the compound (2-methyl-3-chlorocyclohexanol) and no alphabetical order to name the compound (2-methyl-5-chlorocyclohexanol), the correct option is:

5-chloro-2-methylcyclohexanol

Have a nice day!

4 0

3 years ago

A sample of Xe gas is observed to effuse through a pourous barrier in 4.83 minutes. Under the same conditions, the same number o

Solnce55 [7]

Answer:

28.93 g/mol

Explanation:

This is an extension of Graham's Law of Effusion where $\frac{R1}{R2} = \sqrt{\frac{M2}{M1} } = \frac{t2}{t1}$

We're only talking about molar mass and time (t) here so we'll just concentrate on $\sqrt{\frac{M2}{M1} } = \frac{t2}{t1}$ . Notice how the molar mass and time are on the same position, recall effusion is when gas escapes from a container through a small hole. The time it takes it to leave depends on the molar mass. If the gas is heavy, like Xe, it would take a longer time (4.83 minutes). If it was light it would leave in less time, that gives us somewhat an idea what our element could be, we know that it's atleast an element before Xenon.

Let's plug everything in and solve for M2. I chose M2 to be the unknown here because it's easier to have it basically as a whole number already.

$\sqrt{\frac{M2}{131} } = \frac{2.29}{4.83}$

The square root is easier to deal with if you take it out in the first step, so let's remove it by squaring each side by 2, the opposite of square root essentially.

$(\sqrt{\frac{M2}{131} } )^2= (\frac{2.29}{4.83})^2$

${\frac{M2}{131} } = (0.47)^2$

${\frac{M2}{131} } = 0.22$

M2= 0.22 x 131

M2= 28.93 g/mol

8 0

2 years ago

aluminum bromide reacts with chlorine gas to produce aluminum chloride and bromide gas. if we have 9 moles of chlorine gas. how

Luda [366]

Moles of Bromine produced = 9 moles

<h3>Further explanation</h3>

Given

9 moles of Chlorine gas

Word equation

Required

Moles of Chlorine produced

Solution

We change the word equation into a chemical equation (with a formula)

Aluminum bromide reacts with chlorine gas to produce Aluminum chloride and bromide gas

2AlBr₃+3Cl₂⇒2AlCl₃+3Br₂

moles Cl₂ = 9

Maybe you mean, how many moles of Bromine can we produce?

From equation, mol ratio Cl₂ : Br₂ = 3 : 3, so mol Br₂=mol Cl₂=9 moles

7 0

3 years ago