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Svetlanka [38]
3 years ago
5

Use the periodic table to calculate the percent composition of hydrogen in hexane.

Chemistry
1 answer:
valina [46]3 years ago
3 0

Answer:

A)16.3% (Hexane's formula is C6H14)

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The vertical columns on the periodic table of elements are called periods
Vlad1618 [11]
Yes, they are called periods. Pls do you need a confirmation on this and if not what is the question?
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3 years ago
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how would a chemical reaction that includes an enzyme differ from a chemical reaction that thats places without an enzyme
alukav5142 [94]
Enzymes offer a faster pathway for the reaction to happen, so they lower the activation energy necessary for the reaction to happen. The result is that the reaction will happen faster
6 0
3 years ago
(b) what is the major product of the reaction at very low temperatures?
svlad2 [7]
The reaction is low b/c of  the tempature. that's why.
8 0
3 years ago
Acetylene (c2h2) undergoes combustion in excess oxygen to generate gaseous carbon dioxide and water. given δh°f[co2(g)] = –393.5
Brums [2.3K]
Answer is: 13181,7 kJ of energy <span>is released when 10.5 moles of acetylene is burned.
</span>Balanced chemical reaction: C₂H₂ + 5/2O₂ → 2CO₂ + H₂O.
<span>ΔHrxn = sum of ΔHf (products of reaction) - sum of ΔHf (reactants).</span><span>
Or ΔHrxn = ∑ΔHf (products of reaction) - ∑ΔHf (reactants).
ΔHrxn - enthalpy change of chemical reaction.
<span>ΔHf - enthalpy of formation of reactants or products.
</span></span>ΔHrxn = (2·(-393,5) + (-241,8)) - 226,6 · kJ/mol.
ΔHrxn = -1255,4 kJ/mol.
Make proportion: 1 mol (C₂H₂) : -1255,4 kJ = 10,5 mol(C₂H₂) : Q.
Q = 13181,7 kJ.
8 0
3 years ago
Draw the structure for cis-2,3-dibromo-2-hexene.
padilas [110]
First, draw the 2-hexene. Th is is a molecule of six carbons with a double bond in the second carbon:

      CH3 - CH = CH2 - CH2 - CH2 - CH3

Secong, put one Br on the second carbon and one Br on the third carbon:

    CH3 - CBr = CBr - CH2 - CH2 - CH3

Third, cis means that the two Br are placed in opposed positions, this is drawn with one Br up and the other down. So, you need to represent the position of the Br in the space:


      H   Br          H     H      H
       |    |             |       |       |
H - C - C = C -  C  -  C  -  C - H
       |           |      |       |       |
      H          Br   H     H      H

The important fact to realize is that the two Br are in opposed sides of the molecule.
4 0
3 years ago
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