Answer:
name a food that contain an acid
1. nuts
2. dairy
3. grains
3. meat
Explanation:
Derived quantities are quantities that are calculated from two or more measurements. They include area, volume, and density. The area of a rectangular surface is calculated as its length multiplied by its width. The volume of a rectangular solid is calculated as the product of its length, width, and height.
Answer:
Any element
Explanation:
Any element that produces an extra proton, aka a Hydrogen cation, or H⁺
Answer:
2.9 g/cm³
Explanation:
From the question given above, the following data were obtained:
Mass = 236.376 g
Volume = 81.5 cm³
Density =?
Density can be defined as the mass of a substance per unit volume of the substance. It can be expressed mathematically as:
Density = mass /volume
With the above formula, we can obtain the density of the object as shown below:
Mass = 236.376 g
Volume = 81.5 cm³
Density =?
Density = mass /volume
Density = 236.376 / 81.5
Density = 2.9 g/cm³
Thus, the density of the object is 2.9 g/cm³
The given question is incomplete. The complete question is as follows.
A solution of chloroform (
) and acetone (
) exhibits a negative deviation from Raoult's law. This result implies that:
chloroform-chloroform interactions are stronger than chloroform-acetone interactions.
chloroform-chloroform interactions are weaker than chloroform-acetone interactions.
acetone-acetone interactions are stronger than chloroform-acetone interactions.
acetone-acetone interactions are weaker than chloroform-acetone interactions
chloroform-chloroform interactions are weaker than chloroform-acetone interactions AND acetone-acetone interactions are weaker than chloroform-acetone interactions.
Explanation:
It is known that when the forces between the particles of the mixture are stronger than the forces between the particles in the pure liquids then negative deviations from Raoult's law are observed.
Hence, when a solution of chloroform (
) and Acetone (
) will exhibit a negative deviation from Roult's law.
Then, chloroform-chloroform interactions should be weaker than chloroform-acetone interactions and acetone-acetone interactions must be weaker than Chloroform-Acetone interactions.
thus, we can conclude that for the given situation chloroform-chloroform interactions are weaker than chloroform-acetone interactions AND acetone-acetone interactions are weaker than chloroform-acetone interactions.