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bazaltina [42]
3 years ago
11

What is the fundamental building unit

Chemistry
1 answer:
andrew11 [14]3 years ago
3 0

Answer:

The basic building blocks that make up matter are called atoms.

I hope it's helpful!

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How many atoms are in 4.5 x 1022 moles of CO2?
weeeeeb [17]

The number of atoms : N = 2.709 x 10⁴⁶

<h3>Further explanation</h3>

Given

4.5 x 10²² moles of CO₂

Required

The number of atoms

Solution

The mole is the number of particles(molecules, atoms, ions) contained in a substance  

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

Input the value :

N = 4.5 x 10²² x 6.02 x 10²³

N = 2.709 x 10⁴⁶

8 0
2 years ago
A saturated solution containing sugar and carbon dioxide at 1 atm is pressurized into a 2.00 atm container. Describe what happen
alex41 [277]
<span>As the pressure is increased the solubility of the sugar and carbon dioxide is increased. The pressure of combination leaves little to no separation. There would be no discernable difference between the ingredients used to make the saturated solution.</span>
6 0
3 years ago
What 2 materials mixed together forms a solution?
Charra [1.4K]
Lemonade mix and water

Solvent: Water
Solute: Lemonade mix
3 0
3 years ago
Read 2 more answers
The density of aluminum is 2.7 g/mL if I add a piece of aluminum to a graduated cylinder of water in the water level increases b
viva [34]
The answer would be 5.5g because you have to subtract 8.2 minus 2.7 and you get 5.5g so basically the answer is C.
8 0
3 years ago
How many grams of magnesium metal will react completely with 5.2 liters of 4.0 M HCl?
neonofarm [45]
1) Find the number of mols of HCl in 5.2 liters of 4.0M solution:

n = M*V(L) = 4.0 mol/L * 5.2 L = 20.8 mol

2) Find the number of mols of Mg that will react with 20.8 mol of HCl, using the coefficients of the balanced equation

[1mol Mg / 2 mol HCl] * 20.8 mol HCl = 10.4 mol Mg

3) Transform mol to mass using the atomic mass:

10.4 mol Mg * 24.3 g/mol = 252.7 g of Mg.

4 0
2 years ago
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