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2 years ago

14

A 10-kilogram mass is sliding along a frictionless floor with an acceleration of 5 meters per second squared. What is the magnit

ude of the net force acting on the mass?

1 answer:

Darina [25.2K]2 years ago

5 0

Answer:

50N

Explanation:

Since the floor is frictionless, the net force = mass × acceleration.

given that,

mass = 10kg

and acceleration is 5 m/s²

Thus,

Force = 10 × 5

Force = 50 N

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A bus slows with constant acceleration from 24.0 m/s to 16.0 m/s and moves 50.0 m in the process. (a) How much further does it t

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Answer:

(a) Bus will traveled further a distance of 40 m

(b) It will take 7.5 sec to stop the bus

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We have given initial velocity of the bus u = 24 m/sec

And final velocity v = 16 m/sec

Distance traveled in this process s = 50 m

From third equation of motion we know that $v^2=u^2+2as$

$16^2=24^2+2\times a\times 50$

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s= 90 m

So further distance traveled by bus = 90-50 =40 m

(b) Now as the bus finally stops so final velocity v= 0 m/sec

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