Explanation:
velocity of disc 
lets call (h) 1 m to make it simple.
= 3.614 m/s
m/s pointing towards this:


velocity of hoop=
lets call (h) 1m to make it simple again.
m/s
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The disc is the fastest.
While i'm on this subject i'll show you this:
Solid ball 
solid disc 
hoop 
The above is simplified from linear KE + rotational KE, the radius or mass makes no difference to the above formula.
The solid ball will be the faster of the 3, like above i'll show you.
solid ball: velocity 
let (h) be 1m again to compare.
m/s
solid disk speed 
uniform hoop speed 
solid sphere speed 
Answer:
the diameter of the outside edge of the receiver is 
Explanation:
From the schematic free body diagram illustrating what the question is all about below;
Let represent A to be the vertex where the receiver is being placed
S to be the focus
BP to be equal to r (i.e radius of the outer edge)
BC to be 2 r (i.e the diameter)
Given that AS = 4 in and AP is 18 in
Let AP be x- axis and AY be y -axis
A=(0,0)
S=(4,0) = (0,0)
So that the equation of the parabolic path of the receiver will be:

B = (AP, BP)
B = (18, r)
B lies y² = 16 x
r² = 16 x
r² 16 × 18

Diameter BC = 2r

Answer:
It consists of one proton and one electron. The atomic mass for an atom of hydrogen is one dalton, which is calculated from the lone proton.
Explanation:
Answer: Distance
Explanation: because with force and distance we can determine work, and with work and time we can determine power.
Answer:
ΔE = GMm/24R
Explanation:
centripetal acceleration a = V^2 / R = 2T/mr
T= kinetic energy
m= mass of satellite, r= radius of earth
= gravitational acceleration = GM / r^2
Now, solving for the kinetic energy:
T = GMm / 2r = -1/2 U,
where U is the potential energy
So the total energy is:
E = T+U = -GMm / 2r
Now we want to find the energy difference as r goes from one orbital radius to another:
ΔE = GMm/2 (1/R_1 - 1/R_2)
So in this case, R_1 is 3R (planet's radius + orbital altitude) and R_2 is 4R
ΔE = GMm/2R (1/3 - 1/4)
ΔE = GMm/24R