Why do hurricanes rotate counterclockwise in the northern hemisphere
1 answer:
You might be interested in
Answer:
The answer is .
Explanation:
From the law of gravity,
considering F as a conservative force, ,
the general expression for gravitational potential energy is
,
where G is the gravitational constant, M and m are the mass of the attracting bodies, and r is the distance between their centers. The negative sign is because the force approaches zero for large distances, and we choose the zero of gravitational potential energy at an infinite distance away.
However, as the mass of the Sun is much greater than the mass of the rock, the gravitational acceleration is defined as
,
(the negative sign indicates that the force is an attractive force), and the potential energy between the rock and the Sun is
,
which is actually the total energy of the system, because the rock materializes stationary at this point (there is no radial kinetic energy).
When the rock hits the surface of the Sun, almost all potential energy is converted to kinetic energy, but not all because the Sun is not a puntual mass. So the potential energy converted to kinetic energy is
,
then, the kinetik energy when the rock hits the surface is
,
so
where g is the gravitational acceleration generated by the Sun at R,
.
Answer:
q = 8.57 10⁻⁵ mC
Explanation:
For this exercise let's use Newton's second law
F = ma
where force is magnetic force
F = q v x B
the bold are vectors, if we write the module of this expression we have
F = qv B sin θ
as the particle moves perpendicular to the field, the angle is θ= 90º
F = q vB
the acceleration of the particle is centripetal
a = v² / r
we substitute
qvB = m v² / r
qBr = m v
q =
The exercise indicates the time it takes in the route that is carried out with constant speed, therefore we can use
v = d / t
the distance is ¼ of the circle,
d =
d =
we substitute
v =
r =
let's calculate
r = 2 2.2 10-3 88 /πpi
r = 123.25 m
let's substitute the values
q = 7.2 10-8 88 / 0.6 123.25
q = 8.57 10⁻⁸ C
Let's reduce to mC
q = 8.57 10⁻⁸ C (10³ mC / 1C)
q = 8.57 10⁻⁵ mC