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4 years ago

9

Which planet shown (Venus, Mercury, or Mars) is most likely able to support life now or was able to in the past? Explain your re

asoning.

1 answer:

nadezda [96]4 years ago

8 0

Gfdcbzvzv sh d d u runs eh. Uewneumeu ru

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What is the acceleration of a 113 kg object exposed to a 110 N force. (Round to one decimal place.)

Norma-Jean [14]

Answer:

$\boxed {\boxed {\sf a \approx 1.0 \ m/s^2}}$

Explanation:

We are asked to find the acceleration of an object.

According to Newton's Second Law of Motion, force is the product of mass and acceleration.

$F= m \times a$

We know the object has a mass of 113 kilograms and it is exposed to a 110 Newton force.

Let's convert the units of force to make the problem easier later. 1 Newton is equal to 1 kilogram meter sper second squared. So, the force of 110 Newtons is equal to 110 kilogram meters per second squared.

F= 110 kg*m/s²
m= 113 kg

Substitute the values into the formula.

$110 \ kg*m/s^2=113 \ kg * a$

We are solving for a, the acceleration, so we isolate this variable. It is being multiplied by 113 kilograms. The inverse operation of multiplication is division, so we divide both sides by 113 kg.

$\frac {110 \ kg*m/s^2 }{113 \ kg}= \frac{113 \ kg * a}{113 \ kg}$

$\frac {110 \ kg*m/s^2 }{113 \ kg}=a$

The units of kilograms (kg) cancel.

$\frac {110 m/s^2 }{113 }=a$

$0.973451327 \ m/s^2 = a$

We are asked to round to one decimal place or the tenths place. The 7 in the hundredths place tells us to round the 9 up to a 0, but then we must also round the 0 in the ones place to a 1.

$1.0 \ m/s^2 \approx a$

The acceleration of the object is approximately <u>1.0 meter per second squared.</u>

5 0

3 years ago

A 0.6-m3 gas tank holds 5 moles of nitrogen gas (N2), at a temperature of 320 K. The atomic mass of nitrogen is 14 g/mol, the mo

Bond [772]

Answer:

533.92 m/s

Explanation:

The root-mean-square speed of a gas is given by v = √(3RT/M)

R = molar gas constant = 8.3145 J/mol-K

T = Temperature = 320 K

M = Molar mass of Nitrogen in kg/mol = 2 × 14 × 10⁻³ kg/mol = 28 × 10⁻³ kg/mol

v = √(3RT/M) = √(3 × 8.3145 J/mol-K × 320 K/28 × 10⁻³ kg/mol) = √7981920/28 = √285.068.57 = 533.92 m/s

3 0

3 years ago

Is an apple hanging from a tree konetic energy or potential energy

trapecia [35]

Answer:

Potential

Explanation:

This is because it has not yet fallen, and it has the potential to fall and turn into kinetic energy. When it starts falling, it will be kinetic.

7 0

4 years ago

Read 2 more answers

A 1000 kg elevator accelerates upward at 1.0 m/s2 for 10 m, starting from rest. a. How much work does gravity do on the elevator

cricket20 [7]

Answer:

a)= 98kJ

b)=108kJ

c) = 10kJ

Explanation:

a. The work that is done by gravity on the elevator is:

Work = force * distance

= mass * gravity * distance

= 1000 * 9.81 * 10

= 98,000 J

= 98kJ

b)The net force equation in the cable

T - mg = ma

T = m(g+a)

T = 1000(9.8 + 10)

T = 10800N

The work done by the cable is

W = T × d

= 10800N × 10

= 108000

=108kJ

c) PE at 10m = 1000 * 9.81 * 10 = 98,100 J

Work done by cable = PE +KE

108,100 J = KE + 98,100 J

KE = 10,000 J

= 10kJ

=

7 0

3 years ago

Read 2 more answers

Which of the following is not a benefit of improved cardio-respiratory fitness?

givi [52]

I wanna say it’s D. Slower post exercise recovery time.

8 0

4 years ago