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ohaa [14]
2 years ago
10

How to convert 8 feet to metres​

Physics
2 answers:
adelina 88 [10]2 years ago
8 0

Hello there,

We know that 1 foot = 0.305 metre.

So, 8 feet = 8 x 0.305

→ <u>2.438</u><u> </u><u>m.</u>

✍️ <em>By </em><em>Benjemin</em> ☺️

ohaa [14]2 years ago
7 0

Answer:

2.4384m

Explanation:

1 ft in m is 0.3048

8ft in m is x

therefore 8ft in m is

8 * 0.3048 = 2.4384

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2 years ago
the summer camps had field from the campus to fragrance hill. they traveled at an average speed of 65 km/h in the first 2 hours.
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5 hours

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6 0
4 years ago
A charge of -3.40 nC is placed at the origin of an xy-coordinate system, and a charge of 2.45 nC is placed on the y axis at y =
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Answer:

The magnitude of this force is 1.866\times10^{-4}\ N

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Explanation:

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F_{13}=\dfrac{kq_{1}q_{3}}{r^2}

Put the value into the formula

F_{13}=\dfrac{9\times10^{9}\times(-3.40\times10^{-9})\times5.00\times10^{-9}}{(2.90\times10^{-2})^2}

F_{13}=-0.00018192\ N

F_{13}=-1.82\times10^{-4}\ N

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Using formula of force

F_{12}=\dfrac{kq_{1}q_{2}}{r^2}

Put the value into the formula

F_{12}=\dfrac{9\times10^{9}\times(-3.40\times10^{-9})\times2.45\times10^{-9}}{(4.25\times10^{-2})^2}

F_{12}=-0.00004150\ N

F_{12}=-4.15\times10^{-5}\ N

The magnitude of this force is

The total force exerted on this charge by the other two charges.

F=\sqrt{F_{13}^2+F_{12}^2+2F_{13}F_{12}\cos \theta}

Here, \theta=90

F=\sqrt{F_{13}^2+F_{12}^2}

Put the value into the formula

F=\sqrt{(-1.82\times10^{-4})^2+(-4.15\times10^{-5})^2}

F=0.0001866\ N

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(c). We need to calculate the direction of this force

Using formula of direction

\tan\theta=\dfrac{y}{x}

Put the value into the formula

\theta=\tan^{-1}(\dfrac{4.25}{2.90})

\theta=55.69^{\circ}

Hence, The magnitude of this force is 1.866\times10^{-4}\ N

The direction of this force is 55.69°.

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