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4 years ago

How does oxygen concentration affect the fish that live in a pond

2 answers:

7 0

Oxygen is very crucial to the survival of fish in ponds. Fish needs energy to breath. When the concentration of oxygen in the water is reduced as a result of one factor or the other, it leads to the death of the fishes that are living in that pond. The value of oxygen needed in water for fishes to survive ranges from 3 to 10 part per million. The amount of oxygen needed in a pond usually increase as the temperature of the water increases.

Maurinko [17]4 years ago

3 0

Explanation: Oxygen plays a very vital role in the life of aquatic animals. The dissolved oxygen in the water helps them to breathe under water.

Optimum level of oxygen for deep living animals like oysters, bottom feeders, crabs is around (1-6 mg/L), while the animals living on the upper side like fishes require a higher amount of around (4-6 mg/L).

If the oxygen concentration in the pond is not optimum, there will no aquatic life and hence, the ecosystem will be affected.

Hence, oxygen concentration affects the fishes that live in the pond to a higher extent.

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By what factor would a scuba diver’s lungs expand if she ascended rapidly to the surface from a depth of 125 ft without inhaling

vova2212 [387]

It is found that scuba diver’s can safely ascend up to 52.53 ft without Breathing out.

By what factor would a scuba diver’s lungs expand if she ascended rapidly to the surface from a depth of 125 ft without inhaling or exhaling then

$p_{1}$ =patm+ $pH_{2} O$

$p_{1}$ = 101325+ρ $gh_{1}$

It is given that height is 125ft. Put the value of h in above formula:

h1 =125ft=38.1m

ρ=1.04g/mL=1040kg/ $m^{3}$

g=9.81

$p_{1}$ =101325Pa+388711.44

$p_{1}$ =490036.44‬Pa

$p_{2}$ =p atm =101325Pa

It is known that volume and pressure can be expressed as:

V*P=const.

where, V is volume and P is pressure.

Now,

$V_{1} *p_{1}$ = $V_{2} *p_{2}$

$V_{2} /V_{1}$ = $p_{2} /p_{1}$

$V_{2} /V_{1}$ =490036.44/101325

$V_{2} /V_{1}$ =4.84

Assume constant temperature

d of seawater = 1.04 g/mL; d of Hg = 13.5 g/mL.

now $p_{1}$ =p atm+ $pH_{2} O$ =490036.44Pa

V*p=const

where, V is volume and P is pressure.

Now,

$V_{1} *p_{1}$ = $V_{2} *p_{2}$

$V_{2} /V_{1}$ = $p_{2} /p_{1}$

$V_{2} /V_{1}$ =490036.44/X

$p_{2}$ =490036.44pa/(V2/V1) =326690.96Pa

$p_{2}$ =patm +p $H_{2} O$

$p_{2}$ =101325Pa+ρ $gh_{2}$

326690.96Pa=101325Pa+ρ $gh_{2}$

ρgh1 =151987.5-101325=225365.96‬‬Pa

ρ=1,04g/mL=1040kg/m3

g=9.81

$h_{2}$ =225365.96/‬ρ∗g

$h_{2}$ =225365.96 / ‬1040∗9.81

$h_{2}$ =22.09m= 72.47ft

ΔH= $H_{1} -H_{2}$

=125-72.47

=52.53ft

So she can safely ascend up to 52.53 ft without Breathing out

To know more about Scuba diver here

brainly.com/question/15430942

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6 0

1 year ago

Sugar dissolving in tea is it chemical or physical change?

coldgirl [10]

Answer:

it is a physical change because when you heat up again a solution of sugar and tea you gonna obtain again sugar

5 0

3 years ago

Why is argon and chlorine both gases at room temperature?

vredina [299]

<span>Argon and chlorine are both gases at room temperature because they are non-metals.</span>

7 0

3 years ago

Calculate the mass, in grams, of 122 atoms of iron, Fe (1 mol of Fe has a mass of 55.85 g).

vitfil [10]

Answer:

6813.7g

Explanation:

Calculate the mass

Let x be the mass

If 1 mol of Fe has a mass of 55.85 g

1 mol =55.85g

122mol= x

we have x= 122•55.85g=6813.7g

7 0

3 years ago

No FILES PLZZ

Bumek [7]

Answer:

Converted to renewable ones

exhausted or depleted

5 0

3 years ago

Read 2 more answers