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4 years ago

How does oxygen concentration affect the fish that live in a pond

2 answers:

7 0

Oxygen is very crucial to the survival of fish in ponds. Fish needs energy to breath. When the concentration of oxygen in the water is reduced as a result of one factor or the other, it leads to the death of the fishes that are living in that pond. The value of oxygen needed in water for fishes to survive ranges from 3 to 10 part per million. The amount of oxygen needed in a pond usually increase as the temperature of the water increases.

Maurinko [17]4 years ago

3 0

Explanation: Oxygen plays a very vital role in the life of aquatic animals. The dissolved oxygen in the water helps them to breathe under water.

Optimum level of oxygen for deep living animals like oysters, bottom feeders, crabs is around (1-6 mg/L), while the animals living on the upper side like fishes require a higher amount of around (4-6 mg/L).

If the oxygen concentration in the pond is not optimum, there will no aquatic life and hence, the ecosystem will be affected.

Hence, oxygen concentration affects the fishes that live in the pond to a higher extent.

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A chemist designs a galvanic cell that uses these two half-reactions:

Nonamiya [84]

Answer :

(a) Reaction at anode (oxidation) : $4Fe^{2+}\rightarrow 4Fe^{3+}+4e^-$

(b) Reaction at cathode (reduction) : $O_2+4H^++4e^-\rightarrow 2H_2O$

(c) $O_2+4H^++4Fe^{2+}\rightarrow 2H_2O+4Fe^{3+}$

(d) Yes, we have have enough information to calculate the cell voltage under standard conditions.

Explanation :

The half reaction will be:

Reaction at anode (oxidation) : $Fe^{2+}\rightarrow Fe^{3+}+e^-$ $E^0_{anode}=+0.771V$

Reaction at cathode (reduction) : $O_2+4H^++4e^-\rightarrow 2H_2O$ $E^0_{cathode}=+1.23V$

To balance the electrons we are multiplying oxidation reaction by 4 and then adding both the reaction, we get:

Part (a):

Reaction at anode (oxidation) : $4Fe^{2+}\rightarrow 4Fe^{3+}+4e^-$ $E^0_{anode}=+0.771V$

Part (b):

Reaction at cathode (reduction) : $O_2+4H^++4e^-\rightarrow 2H_2O$ $E^0_{cathode}=+1.23V$

Part (c):

The balanced cell reaction will be,

$O_2+4H^++4Fe^{2+}\rightarrow 2H_2O+4Fe^{3+}$

Part (d):

Now we have to calculate the standard electrode potential of the cell.

$E^o=E^o_{cathode}-E^o_{anode}$

$E^o=(1.23V)-(0.771V)=+0.459V$

For a reaction to be spontaneous, the standard electrode potential must be positive.

So, we have have enough information to calculate the cell voltage under standard conditions.

4 0

3 years ago

What are 3 ways animals help the rainforests plants survive

ohaa [14]

Their waste feeds the plants, When animals die they decompose and become natural fertilizer plants. Plants depend on animals for nutrients, pollination and seed dispersal.

7 0

3 years ago

Examples of isotones

lukranit [14]

Answer:

Examples of isotones include carbon-12, nitrogen-13 and oxygen-14. These atoms all have six neutrons and six, seven and eight protons respectively. A mnemonic that can be used to differentiate isotones from isotopes and isobars is as follows: same Z (number of protons) = isotopes.

3 0

3 years ago

Read 2 more answers

The pressure of a 5.0 L sample of gas changes from 3.0 atm to 10.0 atm while the temperature remains constant. What is the gas’s

lina2011 [118]

Answer:

<h2>The answer is 1.5 L</h2>

Explanation:

The new volume can be found by using the formula for Boyle's law which is

$P_1V_1 = P_2V_2$

Since we are finding the new volume

$V_2 = \frac{P_1V_1}{P_2} \\$

From the question we have

$V_2 = \frac{5 \times 3}{10} = \frac{15}{10} = \frac{3}{5} \\$

We have the final answer as

Hope this helps you

8 0

3 years ago

Describe the motion of a ball being thrown straight up in the air in terms of kinetic and potential energy. as the ball rises up

denis23 [38]

In your hand, the ball has higher potential energy than kinetic because it is still off of the ground but it isn't moving so there is no kinetic. As the ball rises, its potential and kinetic energy increases. At its peak, it has very high potential energy and very low kinetic energy. As it falls, the potential energy decreases but kinetic does not.

8 0

3 years ago