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3 years ago

How does oxygen concentration affect the fish that live in a pond

2 answers:

7 0

Oxygen is very crucial to the survival of fish in ponds. Fish needs energy to breath. When the concentration of oxygen in the water is reduced as a result of one factor or the other, it leads to the death of the fishes that are living in that pond. The value of oxygen needed in water for fishes to survive ranges from 3 to 10 part per million. The amount of oxygen needed in a pond usually increase as the temperature of the water increases.

Maurinko [17]3 years ago

3 0

Explanation: Oxygen plays a very vital role in the life of aquatic animals. The dissolved oxygen in the water helps them to breathe under water.

Optimum level of oxygen for deep living animals like oysters, bottom feeders, crabs is around (1-6 mg/L), while the animals living on the upper side like fishes require a higher amount of around (4-6 mg/L).

If the oxygen concentration in the pond is not optimum, there will no aquatic life and hence, the ecosystem will be affected.

Hence, oxygen concentration affects the fishes that live in the pond to a higher extent.

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A photon of green light strikes an unknown metal and an electron is emitted. The voltage is set to 2 volts. The electron cannot

SVETLANKA909090 [29]

Answer:

The correct answer is:

An electron will be emitted in the second experiment, but it cannot be determined whether it will reach the second plate.

Explanation:

In fact, violet has higher frequency than green light. This means that photons on violet carry more energy than photons of green light (remember that the energy of a photon is proportional to it's frequency:

$e = hf$

, so when they hit the surface of the metal, more energy is transferred to the electrons. The electron was already emitted with green light, so it must be emitted with also violet light, given the more energy transferred.

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2 years ago

Calculate the molarity of a solution made by adding 120 g of naoh (40.00 g/mol) to enough water to make 500.0 ml of solution. g

sertanlavr [38]

An: Calculate the molarity of a solution made by adding 120 g of NaOH (40.00 g/mol) to enough water to make 500.0 mL of solution. a) 4.0 M b) 6.0 M c) 1.0 ...

Explanation:

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2 years ago

Combustion of coal releases sulfur dioxide into the atmosphere. The following process converts this gas into sulfuric acid, a co

Usimov [2.4K]

Answer:

$m=7.07gH_{2}SO_{4}$

Explanation:

1. Take in account the sulfuric acid at STP:

$1840\frac{g}{L}$

2. Density is expressed as the ratio between the mass and the volume of a substance so:

$d=\frac{m}{V}$

Solving for m:

$m=\frac{V}{d}$

3. Replace values:

$m=\frac{1.30*10^{4}L}{1840\frac{g}{L}}$

$m=7.07gH_{2}SO_{4}$

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3 years ago

Please help me. Quickly!!!

Tomtit [17]

Answer:

500

Explanation:

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3 years ago

What is the pH of a solution of 1 x 10-5 M NaOH? Is the solution acidic or basic?

Anna007 [38]

Answer: to calculate pH use -log[H+] or - log[OH-]..the solution is basic as the “NaOH” is attached to a hydroxide.Since we need to find the pH (per hydrogen) and not the pOH( per hydroxide) we need to find the pOH of the substance first then we subtract that by 14 so we can arrive at the pH of the substance.

Explanation: So -log( 1 x 10^(-5)) = 5 which is the pOH.Now we subtract that by 14 which gives us -9 and now you’d multiply that by -1 bcuz we can’t have a negative so the pH of the substance is 9

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2 years ago