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avanturin [10]
2 years ago
6

A Person whose weight is 5.20 x 10^2 N is being pulledup

Physics
1 answer:
Gnoma [55]2 years ago
6 0

Answer:

Explanation:

Given

Weight of Person W=5.20\times 10^{2} N

Cave is h=35.1 m deep

Breaking stress T=569 N

Net Force on Person

F_{net}=569-520=49 N

a_{net}=\frac{F_{net}}{\frac{W}{g}}

a_{net}=\frac{49}{\frac{520}{9.8}}

a_{net}=0.923 m/s^2

The shortest time such that the person can be taken out of cave

h=ut+\frac{1}{2}at^2

where

h=distance moved

t=time

a=acceleration

35.1=0+\frac{1}{2}(0.923)(t)^2

t^2=76.05

t=\sqrt{76.05}

t=8.72\ s                    

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VashaNatasha [74]

Answer:

d = 39.7 km

Explanation:

initial position of the boat is 45 km away at an angle of 15 degree East of North

so we will have

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after some time the final position of the boat is found at 30 km at 15 Degree North of East

so we have

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r_2 = 28.98\hat i + 7.76 \hat j

now the displacement of the boat is given as

d = r_2 - r_1

d = (28.98\hat i + 7.76 \hat j) - (11.64 \hat i + 43.46\hat j)

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4 0
3 years ago
The potential difference between the surface of a 3.0-cm-diameter power line and a point 1.0 m distant is 3.9 kV. Find the line
Korolek [52]

Answer:

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Answer:

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3 years ago
The specific heat of gold is 0.126 J/g°C. What mass of gold would change its temperature from 25.0 °C to 60.0 °C with the additi
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<span>The amount of heat energy needed to increase the temperature of a substance by </span>\Delta T<span> is given by:
</span>Q=m C_s \Delta T<span>
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</span>m= \frac{Q}{C_s \Delta T} = \frac{2825J}{0.126\cdot 35}} =641 g<span>
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uranmaximum [27]
D. The car would begin to move in the direction it was headed in a straight line.
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3 years ago
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