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Jlenok [28]
3 years ago
13

. When two speakers play different sounds with a constant frequency, beats are heard with a frequency of 5 Hz. If the frequency

of sound played by one of the speakers is 1050 Hz, what is the frequency of sound played by the other speaker
Physics
1 answer:
morpeh [17]3 years ago
3 0

The beat frequency is the concept required to develop this process. The phenomenon is generated when you have two waves but their frequencies do not differ greatly. So the beat frequency will be the difference between those two waves. For this case we have the difference and one of the waves, therefore,

F_b = |F_1-F_2|

Our values are given as,

F_b = 5Hz

F_1 = 1050Hz

Using the formula of the frequency I will have,

F_b = |F_1-F_2|

Replacing we have,

5 = |1050-F_2|

F_2 = 1050 \pm 5

F_2 = 1045,1055 Hz

The possible values are two: 1045Hz and 1055Hz

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Paula has walked in a straight line, 30.5° north of west, for 1650 meters. How far south and east should she walks to return to
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The answer is A.
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3 years ago
A spring is hung from the ceiling. A 2.0-kg mass suspended hung from the spring extends it by 6.0 cm. A downward external force
Stolb23 [73]

The work done by force on a spring hung from the ceiling will be 1.67 J

Any two things with mass are drawn together by the gravitational pull. We refer to the gravitational force as attractive because it consistently seeks to draw masses together rather than pushing them apart.

Given that a spring is hung from the ceiling with a 2.0-kg mass suspended hung from the spring extends it by 6.0 cm and a downward external force applied to the mass extends the spring an additional 10 cm.

We need to find the work done by the force

Given mass is of 2 kg

So let,

F = 2 kg

x = 0.1 m

Stiffness of spring = k = F/x

k = 20/0.006 = 333 n/m

Now the formula to find the work done by force will be as follow:

Workdone = W = 0.5kx²

W = 0.5 x 333 x 0.1²

W = 1.67 J

Hence the work done by force on a spring hung from the ceiling will be 1.67 J

Learn more about force here:

brainly.com/question/12970081

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8 0
2 years ago
What is the frequency in hertz of a signal that repeats 80,000 times within one minute? What is its period?
Harman [31]

1333.3 is the frequency in the hertz of a signal that repeats 80,000 times within one minute. 0.00075 is its period.

The frequency of a repeated event is its number of instances per unit of time. In some cases, it is also referred to as temporal frequency or ordinary frequency to underline differences with spatial and angular frequencies, respectively.

The length of time it takes for a particle in a medium to complete one full vibrational cycle is the period of a wave. Being a time, a period is measured in time units like seconds, hours, days, or years. The Earth's orbit around the Sun has a duration of around 365 days, and one cycle of the Earth lasts 365 days.

frequency = cycle /second

frequency = 80000 / 60

frequency = 1333.3 hertz

Period = 1 / frequency

Period = 1 / 1,333.3

Period = 0.00075

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5 0
2 years ago
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