Answer:
The answer is B).
Explanation:
The correct way to write this sentence is: After I woke up this morning, I got me a tall glass of orange juice.
Answer: metals.
Justification:
There are 118 elements which you can find in the periodic table ordered by atomic number. Those elements my be classified into metals, non-metals and metalloids.
The metals are placed on the left side of the periodic table. The metals share the properties of luster, conductivity and flexibility.
The properties of non-metals (which are on the right side of the periodic table) are opposite to those of metals: opaque, low conductivity and brittle.
Metalloids have in between properties.
Copper, for example is a metal: it has luster, is flexible and is highly conductive of the electricity (and temperature).
Answer:
7
Explanation:
A substance that is neither acidic nor basic is neutral. The pH scale measures how acidic or basic a substance is. The pH scale ranges from 0 to 14. A pH of 7 is neutral.
Answer:
E=12.2V/m
Explanation:
To solve this problem we must address the concepts of drift velocity. A drift velocity is the average velocity attained by charged particles, such as electrons, in a material due to an electric field.
The equation is given by,
![V=\frac{I}{nAq}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7BI%7D%7BnAq%7D)
Where,
V= Drift Velocity
I= Flow of current
n= number of electrons
q = charge of electron
A = cross-section area.
For this problem we know that there is a rate of 1.8*10^{18} electrons per second, that is
![\frac{I}{q} = 1.2*10^{18}](https://tex.z-dn.net/?f=%5Cfrac%7BI%7D%7Bq%7D%20%3D%201.2%2A10%5E%7B18%7D)
![A= 1.3*10^{-8}m^2](https://tex.z-dn.net/?f=A%3D%201.3%2A10%5E%7B-8%7Dm%5E2)
![n=6.3*10^{28} e/m^3](https://tex.z-dn.net/?f=n%3D6.3%2A10%5E%7B28%7D%20e%2Fm%5E3)
Mobility
We can find the drift velocity replacing,
![V = \frac{1.2*10^{18}}{(1.3*10^{-8})(6.3*10^{28})}](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B1.2%2A10%5E%7B18%7D%7D%7B%281.3%2A10%5E%7B-8%7D%29%286.3%2A10%5E%7B28%7D%29%7D)
![V= 1.465*10^-3m/s](https://tex.z-dn.net/?f=V%3D%201.465%2A10%5E-3m%2Fs)
The electric field is given by,
![E= \frac{V}{\omicron{O}}](https://tex.z-dn.net/?f=E%3D%20%5Cfrac%7BV%7D%7B%5Comicron%7BO%7D%7D)
![E=\frac{1.465*10^-3}{1.2*10^{-4}}](https://tex.z-dn.net/?f=E%3D%5Cfrac%7B1.465%2A10%5E-3%7D%7B1.2%2A10%5E%7B-4%7D%7D)
![E=12.2V/m](https://tex.z-dn.net/?f=E%3D12.2V%2Fm)