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Jlenok [28]
3 years ago
13

. When two speakers play different sounds with a constant frequency, beats are heard with a frequency of 5 Hz. If the frequency

of sound played by one of the speakers is 1050 Hz, what is the frequency of sound played by the other speaker
Physics
1 answer:
morpeh [17]3 years ago
3 0

The beat frequency is the concept required to develop this process. The phenomenon is generated when you have two waves but their frequencies do not differ greatly. So the beat frequency will be the difference between those two waves. For this case we have the difference and one of the waves, therefore,

F_b = |F_1-F_2|

Our values are given as,

F_b = 5Hz

F_1 = 1050Hz

Using the formula of the frequency I will have,

F_b = |F_1-F_2|

Replacing we have,

5 = |1050-F_2|

F_2 = 1050 \pm 5

F_2 = 1045,1055 Hz

The possible values are two: 1045Hz and 1055Hz

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Two violinists are trying to play in tune. However, whenever they play their A string at the same time they hear a beat frequenc
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The possible frequencies for the A string of the other violinist is 457 Hz and 467 Hz.

(3) and (4) is correct option.

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Beat frequency f = 5.0 Hz

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We need to calculate the possible frequencies for the A string of the other violinist

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