Answer:
r = 5.5 ohms
Explanation:
Given:-
- The open circuit voltage, Vo = 3.5 V
- The terminal voltage, Vt = 2.8 V
- The load, R = 22 ohms
- The internal resistance = r
Find:-
What is the generator’s output impedance (pure resistance)?
Solution:-
- We see that the source Voltage (Vo) is not entirely used for the attached load. Some of the source voltage is dropped within due to the source internal resistance or impedance.
- The terminal voltage (Vt) is the amount of Voltage drop across the load. The current drawn by the load I can be determined by Ohm's Law:
Vt = I*R
I = Vt / R
I = 2.8 / 22
I = 0.12727 Amps
- Since, the attached load (R) and the pure impedance (r) of the source are in series. The current ( I ) is constant across both. The potential drop across the pure resistance (r) can be determined from Ohm's law:
Vo - Vt = I*r
r = ( Vo - Vt ) / I
r = ( 3.5 - 2.8 ) / 0.12727
r = 5.5 ohms
Answer:
The volume flow rate of air is 
Explanation:
A random duct is shown in the below attached figure
The volume flow rate is defined as the volume of fluid that passes a section in unit amount of time
Now by definition of velocity we can see that 'v' m/s means that in 1 second the flow occupies a length of 'v' meters
From the attached figure we can see that
The volume of the prism that the flow occupies in 1 second equals

Hence the volume flow rate is 
R=10+15+30
55 is the answer to the question
Answer:
The expression is shown in the explanation below:
Explanation:
Thinking process:
Let the time period of a simple pendulum be given by the expression:

Let the fundamental units be mass= M, time = t, length = L
Then the equation will be in the form


where k is the constant of proportionality.
Now putting the dimensional formula:
![T = KM^{a}L^{b} [LT^{-} ^{2}]^{c}](https://tex.z-dn.net/?f=T%20%3D%20KM%5E%7Ba%7DL%5E%7Bb%7D%20%20%5BLT%5E%7B-%7D%20%5E%7B2%7D%5D%5E%7Bc%7D)

Equating the powers gives:
a = 0
b + c = 0
2c = 1, c = -1/2
b = 1/2
so;
a = 0 , b = 1/2 , c = -1/2
Therefore:

T = 
where k = 