Question

A three-phase Y-connected 50-Hz two-pole synchronous machine has a stator with 2000 turns of wire per phase. What rotor flux would be required to produce a terminal (line-to-line) voltage of 6 kV (rms value)?

Answer 1

Answer:

The answer is "0.0045 Wb"

Explanation:

Using formula:

$\to E_A= \sqrt{2} \pi N_c f \phi\\\\\to \phi = \frac{E_A}{\sqrt{2} \pi N_c f}$                    .......(a)

Calculating the phase voltage of the machine:

$V_\phi = \frac{V_L}{\sqrt{3}}$

    $= \frac{4.16 \times 10^3}{\sqrt{3}}\\\\=2401.7$

Substitute the value from equation (a):

$\phi= \frac{2401}{\sqrt{2} \times \pi \times 2000 \times 60}$

   $=4.503 \times 10^{-3}\\\\= 0.0045 \ wb$

The rotor flux = 0.0045 Wb