Question

A person notices a mild shock if the current along a path through the thumb and index finger exceeds 82 µA. Find the maximum allowable potential difference without shock across the thumb and index finger for a dry-skin resistance of 2.4 × 105 Ω. Answer in units of V.

Answer 1

Answer:

$V_{voltage}=19.68V$

Explanation:

Given data

Current I=82µA=82×10⁻⁶A

Resistance R=2.4×10⁵Ω

to find

Voltage

Solution

From Ohms law we know that:

$V_{voltage}=I_{current}*R_{resistance}\\V_{voltage}=82*10^{-6}*2.4*10^{5} \\V_{voltage}=19.68V$