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Pavlova-9 [17]
3 years ago
10

A person notices a mild shock if the current along a path through the thumb and index finger exceeds 82 µA. Find the maximum all

owable potential difference without shock across the thumb and index finger for a dry-skin resistance of 2.4 × 105 Ω. Answer in units of V.
Physics
1 answer:
Drupady [299]3 years ago
4 0

Answer:

V_{voltage}=19.68V

Explanation:

Given data

Current I=82µA=82×10⁻⁶A

Resistance R=2.4×10⁵Ω

to find

Voltage

Solution

From Ohms law we know that:

V_{voltage}=I_{current}*R_{resistance}\\V_{voltage}=82*10^{-6}*2.4*10^{5}   \\V_{voltage}=19.68V

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What is the angular displacement of the second hand on a clock after 59 seconds?
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Answer:

a. -6.17 rad

Explanation:

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3 years ago
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Two speakers, one directly behind the other, are each generating a 240-Hz sound wave. What is the smallest separation distance b
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The smallest separation distance between the speakers is 0.71 m.

Explanation:

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v=f\lambda\\\\\lambda=\dfrac{v}{f}\\\\\lambda=\dfrac{343\ m/s}{240\ Hz}\\\\\lambda=1.42\ m

To produce destructive interference at a listener standing in front of them,

d=\dfrac{\lambda}{2}\\\\d=\dfrac{1.42}{2}\\\\d=0.71\ m

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3 years ago
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A 4.0 kg circular disk slides in the x- direction on a frictionless horizontal surface with a speed of 5.0 m/s as shown in the a
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Solution :

Let $m_1=m_2=4$ kg

$u_1 = 5$ m/s

Let $v_1$ and $v_2$ are the speeds of the disk $m_1$ and $m_2$  after the collision.

So applying conservation of momentum in the y-direction,

$0=m_1 .v_1_y -m_2 .v_2_y $

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$v_2 = v_1 \times \frac{\sin 60}{\sin 30}$

$v_2=1.732 \times v_1$

Therefore, the disk 2 have greater velocity and hence more kinetic energy after the collision.

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Therefore, speed of the disk 2 after collision is 4.33 m/s

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3 years ago
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