Question

A vector points -1.55 units along the x-axis and 3.22 units along the y-axis what is the magnitude of the vector

Answer 1

Answer:

3.57 units

Explanation:

$x =\sqrt{ (-1.55)^2+(3.22)^2} = 3.57 units$

Answer 2

Answer:

The magnitude of the vector is 3.57 units.

Explanation:

The x component of the vector, $v_x=-1.55\ \text{units}$

The y component of the vector is $v_y=3.22\ \text{units}$

We need to find the magnitude of the vector. We know that the magnitude of the vector is given by :

$v=\sqrt{v_x^2+v_y^2}$

$v=\sqrt{(-1.55)^2+(3.22)^2}$

$v=3.57\ \text{units}$

So, the magnitude of the vector is 3.57 units. Hence, this is the required solution.