Answer:
23.96 N
Explanation:
From the question given above, the following data were obtained:
Mass of Chihuahua (m) = 3.63 kg
Velocity (v) = 3.3m/s
Time (t) = 0.50 s
Force (F) =?
Next, we shall determine the acceleration of the Chihuahua. This can be obtained as follow:
Velocity (v) = 3.3m/s
Time (t) = 0.50 s
Acceleration (a) =?
a = v/t
a = 3.3/0.5
a = 6.6 m/s²
Thus, the acceleration of the Chihuahua is 6.6 m/s².
Finally, we shall determine the force need to stop the Chihuahua as shown below:
Mass of Chihuahua (m) = 3.63 kg
Acceleration (a) = 6.6 m/s².
Force (F) =?
F = ma
F = 3.63 × 6.6
F = 23.96 N
Therefore, a force of 23.96 N is needed to stop the Chihuahua.
Answer:
T=7.4 N hence T<30 N
Explanation:
The figure is likely to be similar to the one attached. Writing the equation for forces we have
F-T=Fa/g where F is the force, T is tension, a is acceleration and g is acceleration due to gravity. Substituting the figures we have the first equation as
30 N - T = (30/9.81)a
Also, we know that T=F*a/g and substituting 10N for F we obtain the second equation as
T = (10/9.81)a
Adding the first and second equations we obtain
30 = 4.077471967
a Hence

and T=a hence
T is approximately 7.4 N
Answer:
hi apner how is ur going for the weekend on your way home
Explanation:
hi there is that something you could help me
Answer:
1020 km
Explanation:
A complete rotation of the wheel equals a distance of 1 circumference.
The circumference is

where <em>d</em> is the diameter of the wheel.
300,000 rotations = 
In kilometers, this is = 1017876/1000 km = 1020 km
The momentum goes to the wall