Zn + H₂SO₄ = ZnSO₄ + H₂
answer (3) <span>single replacement
hope this helps!</span>
Answer:
A) chlorine
Explanation:
To solve this question we can use:
PV = nRT
In order to solve the moles of the gas. With the moles and the mass we can find the molar mass of the gas to have an idea of its identy:
PV = nRT
PV / RT = n
<em>Where P is pressure: 603mmHg * (1atm / 760mmHg) = 0.7934atm</em>
<em>V = 100mL = 0.100L</em>
<em>R is gas constant = 0.082atmL/molK</em>
<em>T is absolute temperature = 14°C + 273.15 = 287.15K</em>
0.7934atm*0.100L / 0.082atmL/molK*287.15K = n
3.37x10⁻³ moles of the gas
In 0.239g. The molar mass is:
0.239g / 3.37x10⁻³ moles = 70.9g/mol
The gas with this molar mass is Chlorine, Cl₂:
<h3>A) chlorine
</h3><h3 />
<u>Answer</u>:
The phenomenon of marble cancer is due to ACID RAIN.
<u>Explanation</u>:
The marble corrosion is a process by which the marbles or limestone used in construction of monuments and buildings is corroded away by the acid rain. The sulphur-dioxide and nitrogen oxides present in the atmosphere undergoes certain chemical reaction causing this acid rain. These chemical in the acid rain converts the calcium present in the limestone or marble into salt.
Also, this marble cancer leads to change the appearance and color. Sometime due to over corrosion the monuments or building causes them disintegrate .Tajmahal is one of the monument affected by marble cancer. the white color of tai mahal is slowly turning into yellow due to this marble cancer.
Answer:
0.221M
Explanation:
From the question ,
The Molarity of AgNO₂ = 0.310 M
Hence , the concentration of Ag⁺ = 0.301 M
The volume of AgNO₂ = 250 mL
and,
The Molarity of Sodium chromate = 0.160 M
The volume of Sodium chromate = 100 mL.
As the solution is mixed the final volume becomes ,
250mL +100mL = 350mL
Now, using the formula , to find the final molarity of the mixture ,
M₁V₁ ( initial ) = M₂V₂ ( final )
substituting the values , in the above equation ,
0.310M * 250ml = M₂ * 350ml
M₂ = 0.221M
Hence , the concentration of the silver in the final solution = 0.221M
