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krok68 [10]
3 years ago
14

Please answer this question!!​

Mathematics
1 answer:
Nesterboy [21]3 years ago
7 0

Answer:

3

Step-by-step explanation:

A = C

6x + 11 = 3x +20

3x = 9

x = 3

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11x7/8 pls helpp i am so close from my test being over ty
Feliz [49]

Answer:

Exact Form:

77 /8

Decimal Form:

9.625

Mixed Number Form:

9  5 /8

Step-by-step explanation:

I AM SO SORRY IF THIS IS WRONG

3 0
3 years ago
Read 2 more answers
What should you do when solving consecutive integer problems
Lemur [1.5K]
Step 1. Identify the variable.
Step 2. Write an algebraic equation.
Step 3. Solve the equation.
Step 4. Answer the equation.
Step 5. Check answer.
Hope this helps...?
3 0
4 years ago
A games shop sells marbles
Taya2010 [7]
To start, the question is asking for surface area of a cylinder, meaning you will have to use this formula to find it: A=2πrh+2πr^2.

Since you already know that the diameter of the plastic cylinder is 4 marbles long, and each marble is 2 cm in diameter, you would multiply 4 and 2 to get that your diameter is 8 cm. However, since the surface area of a cylinder formula uses radius, you would simply divide 8 by 2 to get that the radius of the cylinder is 4 cm. 

Now, since you already know that the height of the cylinder is equal to 10 marbles, multiply the amount of marbles by 2 to get that the height of the cylinder is 20 cm. 

Now that you know the height and the diameter of the cylinder, plug the values into the formula: A=2π(4)(20)+2π(4)^2.
Assuming that pi is 3.14, simplify the equation as according to PEMDAS and you get that the area of plastic needed to make one cylinder is 602.88 cm squared
5 0
4 years ago
9000 for 5 years at 4.5% compounded monthly
tatuchka [14]
I think its 9000(1.045)^5. Hope this helps. That equals $11,215.60, or rounded to the nearest dollar, $11,215.
7 0
3 years ago
How do you do this question?
daser333 [38]

Answer:

B. 1/2

Step-by-step explanation:

\lim_{z \to 0} \frac{g(z)e^{-z}-3}{z^{2}-2z}

If we plug in 0 for z, we get 0/0.  Apply l'Hopital's rule.

\lim_{z \to 0} \frac{-g(z)e^{-z}+g'(z)e^{-z}}{2z-2}

Now when we plug in 0 for z, we get:

\frac{-g(0)e^{0}+g'(0)e^{0}}{2(0)-2}\\\frac{-g(0)+g'(0)}{-2}\\\frac{-3+2}{-2}\\\frac{1}{2}

4 0
3 years ago
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