What is the modern periodic table of elements?

when two object P and Q are supplied with the same quantity of heat, the temperature change in P is observed to be twice that of

Ahat [919]

<h2>When two object P and Q are supplied with the same quantity of heat, the temperature change in P is observed to be twice that of Q. The mass of P is half that of Q. The ratio of the specific heat capacity of P to Q</h2>

Explanation:

Specific heat capacity

It is defined as amount of heat required to raise the temperature of a substance by one degree celsius .

It is given as :

Heat absorbed = mass of substance x specific heat capacity x rise in temperature

or ,

Q= m x c x t

In above question , it is given :

For Q

mass of Q = m

Temperature changed =T₂/2

Heat supplied = x

Q= mc t

or

X=m x C₁ X T₁

or, X =m x C₁ x T₂/2

or, C₁=X x 2 /m x T₂ (equation 1 )

For another quantity : P

mass of P =m/2

Temperature= T₂

Heat supplied is same that is : X

so, X= m/2 x C₂ x T₂

or, C₂=2X/m. T₂ (equation 2 )

Now taking ratio of C₂ to c₁, We have

C₂/C₁= 2X /m.T₂ /2X /m.T₂

so, C₂/C₁= 1/1

so, the ratio is 1: 1

8 0

4 years ago

Maria is a geologist studying a particular rock layer in a local mountain range. One of her colleagues had previously discovered

NARA [144]

Answer:

Relative dating methods are unable to determine the absolute age of an object or event, but can determine the impossibility of a particular event happening before or after another event of which the absolute date is well known.

So, Maria is using relative dating method

It's the only answer

5 0

3 years ago

The ramp has an efficiency of 80%. If you perform 600 J of work, how much useful work does the ramp do

PIT_PIT [208]

The ramp does 480J of useful work with an efficiency of 80% .

<h3>What is efficiency of work done ?</h3>

Efficiency is the ratio of the useful energy released by a system to the input energy .
Mathematically, efficiency of energy = out put energy/ input energy

<h3>What is the useful work done by the ramp having efficiency 80% and an input work done 600J?</h3>

The efficiency =output work done/ input work done
80% =output work done/ 600J
output work done =( 80×600)/100

=480J

Thus, we can conclude that the useful work done by the ramp is 480J.

Learn more about efficiency of energy here:

brainly.com/question/14280607

#SPJ1

5 0

2 years ago

A car is traveling at 100 km/h. How many hours will it take to cover a<br> distance of 750 km?

dem82 [27]

Answer:

7 hours and 30 mins

Explanation:

4 0

3 years ago

Read 2 more answers

A slit 0.240mm wide is illuminated by parallel light rays with a wavelength 600nm . The diffraction pattern is observed on a scr

taurus [48]

To solve this exercise, it is necessary to apply the concepts on the principle of superposition, specifically on constructive interference,

Constructive interference (light spot) is defined by

$dsin\theta=m\lambda$

Where,

m = The integer m is called the interference order and is the number of wavelengths by which the two paths differ.

$\lambda = wavelenght$

d = Distance

For smaller angles $sin\theta = tan\theta$ ,

$d tan\theta = m \lambda$

From the trigonometric properties it is understood that so the is - in this case - the length measured vertically by reason of distance, that is

$d*\frac{y}{L} = m\lambda$

Re-arrange to find y,

$y = \frac{m\lambda L}{d}$

Replacing our values

$y = \frac{(1)(600*10^{-9}(3.5m)}{0.240*10^{-3}m}$

$y = 8.75*10^{-3}m$

$y = 8.75mm$

PART B) To calculate the intensity it is necessary to find the angle between the previously calculated height and distance in order to calculate the phase angle, in other words,

$tan\theta' = \frac{y}{L}$