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just olya [345]
3 years ago
11

Help me plzzzz i have a f in this classs ​

Mathematics
1 answer:
Helen [10]3 years ago
3 0

Answer:

yes it is. ")

Step-by-step explanation:

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Is a measure of 26 inches​ "far away" from a mean of 16 ​inches? As someone with knowledge of​ statistics, you answer​ "it depen
alexandr402 [8]

Answer: Hello!

In a normal distribution, between the mean and the mean plus the standar deviation, there is a 34.1% of the data set, between the mean plus the standar deviation, and the mean between two times the standard deviation, there is a 16.2% of the data set, and so on.

If our mean is 16 inches, and the measure is 26 inches, then the difference is 10 inches between them.

a) if the standar deviation is 2 inches, then you are 10/2 = 5 standar deviations from the mean.

b) yes, is really far away from the mean, in a normal distribution a displacement of 5 standar deviations has a very small probability.

c) Now the standar deviation is 7, so now 26 is in the range between 1 standar deviation and 2 standar deviations away from the mean.

Then this you have a 16% of the data, then in this case, 26 inches is not far away from the mean.

3 0
3 years ago
The square of a number is the input and the output is the number.
Dimas [21]
What is your question?????
5 0
3 years ago
Read 2 more answers
The figure below is not drawn to scale. ABCD is a parallelogram, Find
Butoxors [25]

\angle BAD=100^{\circ} (opposite angles in a parallelogram)

\angle EAD=80^{\circ} (subtraction)

\angle ADE=65^{\circ} (angles in a triangle add to 180 degrees)

\angle CDA=80^{\circ} (adjacent angles in a parallelogram are supplementary)

\boxed{\angle CDE=15^{\circ}} (subtraction)

\angle CED=65^{\circ} (angles in a triangle add to 180 degrees)

\boxed{\angle AEB=80^{\circ}} (angles on a straight line add to 180 degrees)

4 0
2 years ago
A bank sampled its customers to determine the proportion of customers who use their debit card at least once each month. A sampl
Zinaida [17]

Answer:

(0.084,0.396)

Step-by-step explanation:

The 99% confidence interval for the proportion of customers who use debit card monthly can be constructed as

p-z_{\frac{\alpha }{2}} \sqrt{\frac{pq}{n} }

p=\frac{x}{n}

p=\frac{12}{50}

p=0.24

q=1-p=1-0.24=0.76

\frac{\alpha }{2} =\frac{\0.01 }{2}=0.005

p-z_{\frac{\alpha }{2}} \sqrt{\frac{pq}{n} }

0.24-z_{0.005} \sqrt{\frac{0.24*0.76}{50} }

0.24-2.58(0.0604)

0.24-0.155832

By rounding to three decimal places we get,

0.084

The 99% confidence interval for the proportion of customers who use debit card monthly is (0.084,0.396).

3 0
3 years ago
If your dinner bill was $80 and you left a 15% tip. How much money did you leave as a tip? What is your total bill cost?
nadya68 [22]

Answer: 92 dollars because 15% divided into 80 is 12 and add 80 to 12 and its 92

6 0
3 years ago
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