The mole ratio of iron to copper is 1 : 1, thus, 1.31 g of iron is required to produce 1.5 g of copper.
<h3>What is the equation of the reaction between iron and copper(ii) sulfate?</h3>
The reaction between iron and copper(ii) sulfate is a redox displacement reactions in which copper is displaced from its salt by iron.
The equation of the reaction is given below:
The mole ratio of both reactants and product is 1 : 1
molar mass of copper sulfate = 160 g
molar mass of Cu = 64
molar mass of iron = 56 g
- mole ratio of iron to copper = 1 : 1
moles of Cu in 1.5 g = 1.5/64 = 0.00234
mass of iron required = 0.00234 × 56 = 1.31 g of iron
Therefore, from the mole ratio of iron to copper, 1.31 g of iron is required to produce 1.5 g of copper.
Learn more about mole ratio at: brainly.com/question/19099163
Answer:
Explanation:
We have the ideal gasses equation 
and the expression for the specific volume 
, that is the inverse of the density, and for definition the number of moles is equal to the mass over the molar mass, that is 
And we can relate the three equations as follows:
Replacing the expression for n, we have:
Replacing the expression for v, we have:
Now resolving for T, we have:
Now, we should convert all the quantities to the same units:
-Convert 500kPa to atm
-Convert 0.2
to 
- Convert the molar mass M of the water from 
to 
Finally we can replace the values:
P = 2.30 atm
Volume in liter = 2.70 mL / 1000 => 0.0027 L
Temperature in K = 30.0 + 273 => 303 K
R = 0.082 atm
molar mass O2 = 31.9988 g/mol
number of moles O2 :
P * V = n * R* T
2.30 * 0.0027 = n * 0.082 * 303
0.00621 = n * 24.846
n = 0.00621 / 24.846
n = 0.0002499 moles of O2
Mass of O2:
n = m / mm
0.0002499 = m / 31.9988
m = 0.0002499 * 31.9988
m = 0.008 g
Radioactive material obeys 1st order decay kinetics,
For 1st order reaction, we have
k =
where, k = rate constant of reaction
Given: Initial conc. 100, Final conc. = 6.25, t = 18.9 hours
∴ k =
= 0.1467 hours^(-1)
Now, for 1st order reactions: half life =
= 4.723 hours.
