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s2008m [1.1K]
3 years ago
9

As temperature increase and the volume stays constant, how will the pressure change

Chemistry
1 answer:
crimeas [40]3 years ago
5 0

Answer:

There will be more collisions and so a greater pressure. The number of particles is proportional to pressure, if the volume of the container and the temperature remain constant. ... Volume is inversely proportional to pressure, if the number of particles and the temperature are constant.

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What is the role of plastocyanin in the z-scheme model?
murzikaleks [220]

Answer:

It shuttles electrons between the cytochrome complex and photosystem I.

Explanation:

6 0
2 years ago
How many grams of KCI can be dissolved in 63.5. g of water at 80
Masteriza [31]

Answer:

35.8 g

Explanation:

Step 1: Given data

Mass of water: 63.5 g

Step 2: Calculate how many grams of KCl can be dissolved in 63.5. g of water at 80 °C

Solubility is the maximum amount of solute that can be dissolved in 100 g of solute at a specified temperature. The solubility of KCl at 80 °C is 56.3 g%g, that is, we can dissolve up to 56.3 g of KCl in 100 g of water.

63.5 g Water × 56.3 g KCl/100 g Water = 35.8 g KCl

8 0
3 years ago
Why is it important to collect all data during experiments, rather than make inferences of what will happen?
Paraphin [41]

Answer:

It is important to collect all data first, or else your guesses could purely be the opposite of the right answer. If you make inferences of what might happen, your guesses may be purely fictional, and totally off-topic. During experiments, this step is important.

7 0
3 years ago
Still using the reaction from the video, what is the limiting reagent when 2 moles of Al are reacted
kondaur [170]

The limiting reagent will be Al

<h3>What are limiting reagents?</h3>

They are reagents that limit the quantity of products that are formed in reactions.

From the equation of the reaction:

4Al + 3O_2 --- > 2Al_2O_3

The mole ratio of Al to O2 is 4:3.

With 2 moles of Al and 2 moles of O2, Al becomes limiting while O2 is in excess.

With 2 moles of O2, the amount of Al required should be:

                          2 x 4/3 = 2.67 moles.

With 2 moles of Al, the amount of O2 required should be:

                    2 x 3/4 = 1.5 moles

Thus, O2 is in excess by 0.5 moles.

More on limiting reagents can be found here: brainly.com/question/11848702

#SPJ1

8 0
2 years ago
If you have 2 solutions: one equal to 9mol/L and another with 6 mol/L,
tamaranim1 [39]

Answer:

Explanation:

8iiuhffhkkiiuyhhhgjdnsifje

7 0
3 years ago
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