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kupik [55]
3 years ago
7

Consider two solutions made using water as the solvent: 1.0 m CaCl2 and 3.0 m sucrose. Describe how the osmotic pressures of the

se two solutions compare. Explain why this is true.
Chemistry
2 answers:
Setler [38]3 years ago
8 0

The osmotic pressures of the two solutions are the same.

Both solutions contain the same number of dissolved particles in the same quantity of the same solvent.

Osmotic pressure is a colligative property.

Because it is a colligative property, osmotic pressure is influenced only by the number of dissolved particles, not by the identities of the particles.

mash [69]3 years ago
7 0
Osmotic pressure is calculated by the product of the concentration in molarity, the  temperature, the vant Hoff factor (3 for CaCl2 and 1 for sucrose) and R, universal gas constant. At the same temperature, the osmotic pressures of both solutions are equal.

π = CRTi
For CaCl2,
π = (1)RT(3) = 3RT

For sucrose,
π = (3)RT(1) = 3RT
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The specific branch of chemistry that focuses on molecules such as salts and water that constitute non-living matter, but are st
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Answer: Inorganic chemistry

Explanation:

Inorganic chemistry can be defined as the branch of chemistry which studies the behavior of the inorganic compounds. Inorganic compounds are those compounds which lack carbon hydrogen bonding. The carbon monoxide, carbon dioxide, sodium chloride and water are the examples of inorganic compounds. This branch also studies the effect of these chemical compounds on the living things. The water and salts are chemicals which regulate the chemical and physiological reactions in the body.

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3 years ago
A kilogram is an SI unit. Which quantity might you measure in kilograms? temperature
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The quantity that you would measure in kg, is mass.
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A 0.652-g sample of a pure strontium halide reacts with excess sulfuric acid. the solid strontium sulfate formed is separated, d
seraphim [82]

Answer:

The formula of the original halide is SrCl₂.

Explanation:

  • The balanced equation of this reaction is:

SrX₂ + H₂SO₄ → SrSO₄ + 2 HX, where X is the halide.

  • From the equation stichiometry, 1.0 mole of strontium halide will result in 1.0 mole of SrSO₄.
  • The number of moles of SrSO₄ <em>(n = mass/molar mass) </em>= (0.755 g) / (183.68 g/mole) = 4.11 x 10⁻³ mole.
  • The number of moles of SrX are  4.11 x 10⁻³ moles from the stichiometry of the balanced equation.
  • n = mass / molar mass, n =  4.11 x 10⁻³ moles and mass = 0.652 g.
  • The molar mass of SrX₂ = mass / n = (0.652) / (4.11 x 10⁻³ moles) = 158.62 g/mole.
  • The molar mass of SrX₂ (158.62 g/mole) = Atomic mass of Sr (87.62 g/mole) + (2 x Atomic mass of halide X).
  • The atomic mass of halide X = (158.62 g/mole) - (87.62 g/mole) / 2 = 71 / 2  g/mole = 35.5 g/mole.
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3 years ago
Please hurry and tell the answer to:
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Answer:

6.50 g of Hydrogen

Explanation:

We know that in every 20.0g of sucrose, there are 1.30g of hydrogen.

We now have 100.0g of sucrose. 100.0g is 5x larger than the 20.0g sample, which is a 5 : 1 ratio. Applying this ratio to the amount of hydrogen, we would have 5*1.3g of hydrogen in the 100.0g of sucrose.

5*1.3 = 6.5, so our answer is that there are 6.50g of hydrogen in 100.0g of sucrose.

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