Answer:
A.)
Explanation:
Just took this test and got the question right!
Answer:
7,94 minutes
Explanation:
If the descomposition of HBr(gr) into elemental species have a rate constant, then this reaction belongs to a zero-order reaction kinetics, where the r<em>eaction rate does not depend on the concentration of the reactants. </em>
For the zero-order reactions, concentration-time equation can be written as follows:
[A] = - Kt + [Ao]
where:
- [A]: concentration of the reactant A at the <em>t </em>time,
- [A]o: initial concentration of the reactant A,
- K: rate constant,
- t: elapsed time of the reaction
<u>To solve the problem, we just replace our data in the concentration-time equation, and we clear the value of t.</u>
Data:
K = 4.2 ×10−3atm/s,
[A]o=[HBr]o= 2 atm,
[A]=[HBr]=0 atm (all HBr(g) is gone)
<em>We clear the incognita :</em>
[A] = - Kt + [Ao]............. Kt = [Ao] - [A]
t = ([Ao] - [A])/K
<em>We replace the numerical values:</em>
t = (2 atm - 0 atm)/4.2 ×10−3atm/s = 476,19 s = 7,94 minutes
So, we need 7,94 minutes to achieve complete conversion into elements ([HBr]=0).
Answer:
Explanation:
Let assume that the missing aqueous solution of 4-chlorobutanoic acid = 0.76 M
Then, the dissociation of 4-chlorobutanoic acid can be expressed as:
⇄
+ 
The ICE table can be computed as:
⇄
+ 
Initial 0.76 - -
Change -x +x +x
Equilibrium 0.76 - x x x
![K_a = \dfrac{[\mathsf{C_3H_6ClCO_2^-}] [\mathsf{H^+}]}{\mathsf{[C_3H_6ClCO_2H ]}}](https://tex.z-dn.net/?f=K_a%20%3D%20%5Cdfrac%7B%5B%5Cmathsf%7BC_3H_6ClCO_2%5E-%7D%5D%20%5B%5Cmathsf%7BH%5E%2B%7D%5D%7D%7B%5Cmathsf%7B%5BC_3H_6ClCO_2H%20%5D%7D%7D)
![K_a = \dfrac{[x] [x]}{ [0.76-x]}](https://tex.z-dn.net/?f=K_a%20%3D%20%5Cdfrac%7B%5Bx%5D%20%5Bx%5D%7D%7B%20%5B0.76-x%5D%7D)
where:

![3.02*10^{-5} = \dfrac{x^2}{ [0.76-x]}](https://tex.z-dn.net/?f=3.02%2A10%5E%7B-5%7D%20%3D%20%5Cdfrac%7Bx%5E2%7D%7B%20%5B0.76-x%5D%7D)
however, the value of x is so negligible:
0.76 -x = 0.76
Then:


x = 0.00479 M
∴
0.00479 M
= (0.76 - 0.00479) M
= 0.75521 M
Finally, the percentage of the acid dissociated is;
= ( 0.00479 / 0.76) × 100
= 0.630 M