You have already gotten the balanced equation. And the ratio of mol number of reactants and production is the ratio of coefficient. So there is 6.4/8*11=8.8 mol oxygen needed. The mass is 8.8*32=281.6 g.
Answer:
Following are the solution to the given question:
Explanation:
Please find the complete question and its solution file in the attachment.
In the balanced equation, we see that the ratio of
is 1:2 respectively. That being said, we can then set up a proportion to solve for the number of moles of water produced from 13.35 moles of oxygen:
![\frac{1mol_{O_{2}}}{2mol_{H_{2}O}} =\frac{13.35mol_{O_{2}}}{xmol_{H_{2}O}}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1mol_%7BO_%7B2%7D%7D%7D%7B2mol_%7BH_%7B2%7DO%7D%7D%20%3D%5Cfrac%7B13.35mol_%7BO_%7B2%7D%7D%7D%7Bxmol_%7BH_%7B2%7DO%7D%7D%20%20)
Then we cross multiply and solve for x:
![x=26.7mol_{H_{2}O}](https://tex.z-dn.net/?f=%20x%3D26.7mol_%7BH_%7B2%7DO%7D%20)
Therefore the answer is B) 26.70 mol.