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Bas_tet [7]
3 years ago
15

Examine the chemical equation Al + O2 Al2O3

Chemistry
1 answer:
AURORKA [14]3 years ago
5 0
I think it is aluminum oxide

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24. When the equation
serg [7]

Answer:

Explanation:

3

Explanation:

The reaction expression is given as:

     Al(OH)₃  +   HNO₃   →    H₂O   +  Al(NO₃)₃  

To solve this problem, let us assign coefficient a,b,c and d to each specie;

          aAl(OH)₃  +   bHNO₃   →    cH₂O   +  dAl(NO₃)₃  

Conserving Al : a  = d

                  O:  3a + 3b  = c + 9d

                  H: 3a + b  = 2c

                  N: b  = 3d

let a = 1 , d  = 1, b  = 3 , c = 3

 Multiply through by 3;

a  = 1, b  = 3, c = 3 and d  = 1

  Al(OH)₃  +   3HNO₃   →    3H₂O   +  Al(NO₃)₃  

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3 years ago
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What type of hydrocarbon is 2-octene, and what about the structure allows 2-octene to be classified as this type of hydrocarbon?
12345 [234]

an alkene because there is a double bond

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A sample of C3H8 has 6.72 x 10^24 H atoms. <br> What is the total mass of the sample?
gregori [183]
The answer is 492.8 g


1. Calculate a number of moles of a sample.
2. Calculate a molar mass of C3H8.
3. Calculate a mass of the sample. 

1. Avogadro's number is the number of units (atoms, molecules) in 1 mole of substance: 6.023 × 10²³ units per 1 mole    

6.023 × 10²³ atoms : 1 mol =6.72 × 10²⁴ atoms : n

n = 6.72 × 10²⁴ atoms * 1 mol : 6.023 × 10²³ atoms = 1.12 × 10 mol = 11.2 mol


2. Molar mass (Mr) of C3H8 is sum of atomic masses (Ar) of its elements:

Ar(C) = 12 g/mol

Ar(H) = 1 g/mol

Mr(C3H8) = 3 * Ar(C) + 8 * Ar(H) = 3 * 12 + 8 * 1 = 36 + 8 = 44 g/mol



3. Mass (m) of a sample is number of moles (n) multiplied by molar mass (Mr) of C3H8:

m = n * Mr = 11.2 mol * 44 g/mol = 492.8 g

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