Answer:
The concentration of the borax solution is 0.1066 M
Explanation:
Step 1: Dtaa given
Volume of a sample of aqueous borax solution = 20.00 mL = 0.020 L
Molarity of H2SO4 = 1.03 M
Volume of the H2SO4 = 2.07 mL = 0.00207 L
Step 2: The balanced equation
Na2B4O7*10H2O(borax) + H2SO4 ⇆ Na2SO4 + 4 H3BO3 + 5 H2O
Step 3: Calculate molarity of borax solution
b*Ca*Va = a * Cb*Vb
⇒with B = the coefficient of H2SO4 = 1
⇒with Ca = the concentration of borax = TO BE DETERMINED
⇒with Va = the volume of borax = 0.020 L
⇒with a = the coefficient of borax = 1
⇒with Cb = the concentration of H2SO4 = 1.03 M
⇒with Vb = the volume of H2SO4 = 0.00207 L
Ca*0.020 L = 1.03 M * 0.00207 L
Ca = (1.03 * 0.00207) / 0.020
Ca = 0.1066 M
The concentration of the borax solution is 0.1066 M
