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Nady [450]
3 years ago
14

Sunlight is a form of electromagnetic energy.

Physics
1 answer:
Sergio039 [100]3 years ago
7 0

Answer: True

Explanation: Hope this helps :)

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Which statement about allele combinations is accurate?
Pepsi [2]

Offspring get two alleles for each trait – one from each parent.

6 0
3 years ago
If two point masses 1kg & 4kg are seperated by a distance of 2m. Magnitude of gravitational force exerted by 1kg on 4kg is ?
Aliun [14]

Answer:

  • F = G Newtons

Explanation:

Given:

  • Mass of 1st body = 1\:kg
  • Mass of 2nd body = 4\:kg

To Find:

  • Magnitude of gravitational force

Solution:

Here, we have a formula

  • F=\dfrac{G.M_{1}.M_{2}}{r^{2}}

<u>Substituting the values</u>

\implies\:\:F = \dfrac{G(1)(4)}{2^{2}}

\implies\:\:F = \dfrac{4G}{4}

\implies\:\:F = \dfrac{\cancel{4}G}{\cancel{4}}

\implies\:\:\red{F = G}

Know More:

The applied formula for the above solution is

{\boxed{F_{G}=\dfrac{G.M_{1}.M_{2}}{r^{2}}}}

where,

  • F_{G} = Gravitational force
  • G = Gravitational constant
  • M_{1} = mass of 1st body
  • M_{2} = mass of 2nd body
  • r = distance between two bodies
6 0
3 years ago
Which of the followijg is an example of kinetic energy
Ipatiy [6.2K]

Answer:

D

Explanation:

D. A swing moving back and forth

3 0
3 years ago
Read 2 more answers
In July 2005, NASA's "Deep Impact" mission crashed a 372-kg probe directly onto the surface of the comet Tempel 1, hitting the s
eimsori [14]

Question:

(a) What change in the comet’s velocity did this collision produce? Would this change be noticeable? (b) Suppose this comet were to hit the earth and fuse with it. By how much would it change our planet’s velocity? Would this change be noticeable? (The mass of the earth is 5.97×1024kg.)

Answer:

The answers to the question are;

(a) The change in the comet’s velocity produced by the collision is 2.86 × 10⁻⁶km/h or 7.944 × 10⁻⁷ m/s

(b) It would change our planet’s velocity by  6.70× 10⁻⁸ km/h or 1.86× 10⁻⁸ m/s

Change is too small to be noticeable

Explanation:

We not that the question is about conservation of liner momentum

Therefore we have, by listing out the known parameters

m₁ = Mass of "Deep Impact" = 372 kg

m₂ = Mass of Tempel 1 comet  = (0.1 to 2.5) × 10¹⁴ kg,

v₁ = Vaelocity of "Deep Impact" = 37000 km/h

v₂ = Velocity of Tempel 1 comet = 40000 km/h

From the principle of linear momentum, we have, for both bodies moving in opposite direction;

m₁×v₁ + m₂×v₂ = m₁×v₃ + m₂×v₃ since it was a crash, it is assumed that they both have the same final velocity

This gives

372 kg ×37000 km/h  - 0.1 × 10¹⁴ kg × 40000 km/h = (372 kg + 0.1 × 10¹⁴ kg )×v₃

13764000 kg·km/h - 4.0 × 10¹⁷  kg·km/h = 10000000000372×v₃

v₃ = (-399999999986236000 kg·km/h)/10000000000372 = -39999.999997 km/h ≈ - 40000  km/h in the direction of Deep Impact

Change in comet velocity

= 40000  km/h - 39999.999997 km/h

= 2.86 × 10⁻⁶km/h = 7.944 × 10⁻⁷ m/s

(b) If the colission is with earth, we have

m₃ = Mass of earth

From the principle of conservation of linear momentum, we have

m₂v₂+m₃ v₃ = (m₂ + m₃) v₄

v₃ = Initial velocity of Earth = 0 km/h

m₃ = Mass of Earth = 5.97 × 10²⁴ kg

Therefore, pluggin in the vaalues gives

0.1 × 10¹⁴ kg × 40000 km/h + 5.97 × 10²⁴ kg × 0 km/h = (0.1 × 10¹⁴ kg + 5.97 × 10²⁴ kg) × v₄

Therefore,

v₄ = (4.0 × 10¹⁷  kg·km/h + 0 kg·km/h)/ (5970000000010000000000000 kg)

= 6.70× 10⁻⁸ km/h = 1.86× 10⁻⁸ m/s

Change is too small

5 0
3 years ago
A certain copper wire has a resistance of 10.5 Ω. It is cut into two pieces such that one piece has 6.0 times the resistance of
S_A_V [24]

Answer:

1.5 ohm, 9 ohm

Explanation:

Total resistance, R = 10.5 ohm

Let the resistance of one piece is r and then the resistance of another piece is 10.5 - r.

According to question, the resistance of one piece is equal to the 6 times the resistance of another piece.

so, 6 r = 10.5 - r

7 r = 10.5

r = 1.5 ohm

Thus, the resistance of one piece is 1.5 ohm and resistance of another piece is 10.5 - 1.5 = 9 ohm.

4 0
3 years ago
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