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Feliz [49]
3 years ago
7

A hair dryer draws 11 A when it is connected to 120 V. If electrical energy costs $ 0.09/kW·h, what is the cost of using the hai

r dryer for exactly 15 min?
Free brainliest, i was planning on answering this myself anyway.

Answer: $0.3

Explanation:
Operating Cost ($) = Energy Use (kWh) x Electric Rate
1. convert Amps to watts
11 x 120= 1320
2. convert watts to kilowatts
1320/1000=1.32
3. convert the time to hours
15/60=0.25
4. Multiply the time and the kilowatts
0.25 x 1.32= 0.33kWh
5. find the cost
0.9 x 0.33= $0.297
Physics
1 answer:
Papessa [141]3 years ago
6 0

Answer:

The cost of using the hair dryer for 15 minutes is \$3.6\bar 6

Explanation:

The parameters given in the question are;

The electric current drawn by the the air dryer, I = 11 A

The voltage to which the hair dryer is connected, V = 120 V

The duration of usage of the hair dryer = 15 minutes = 60 minutes /4 = 1 hour/4 = 0.25 hour

The electrical energy costs $0.09/kW·h

The power consumed by the hair dryer = I × V = 11 × 120 = 1320 Watts = 1.32 kW

The energy used by the hair dryer in 15 minutes (0.25 hour) = 1.32 × 0.25 0.33 kW·h

The energy used by the hair dryer in 15 minutes (0.25 hour) = 0.33 kW·h

The energy cost = $0.09/(kW·h)

Therefore;

The cost of using the hair dryer for 15 minutes (0.25 hour) = 0.33 kW·h/($0.09/(kW·h)) = $33/9 = $3 2/3 = $3.6\bar 6.

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nignag [31]

Answer:

The new resistance comes out to be = 4 times of original resistance .

6 0
3 years ago
As you look at the side of the wheel, you can see it spinning clockwise. What are the directions of the angular velocity, and an
lorasvet [3.4K]

Answer:

The direction of angular velocity and angular momentum are perpendicular to the plane of rotation. Using the right hand rule, the direction of both angular velocity and angular momentum is defined as the direction in which the thumb of your right hand points when you curl your fingers in the direction of rotation.

Explanation:

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3 years ago
At Magic Mountain there is a ride in which people stand up against the inside wall of a large cylinder of radius 3 m. The cylind
mafiozo [28]

Answer:

0.1308

Explanation:

To keep the rider from sliding down, then the friction force F_f must at least be equal to gravity force F_p

F_f = F_p

\mu N = mg

where μ is the coefficient, N is the normal force acted by the rotating cylinder, m is the mass of a person and g = 9.81 m/s2 is the gravitational acceleration.

According to Newton's 3rd and 2nd laws, the normal force would be equal to the centripetal force F_c, which is the product of centripetal acceleration a_c and object mass m

N = F_c = a_cm

Therefore

\mu a_cm = mg

\mu a_c = g

The centripetal acceleration is the ratio of velocity squared and the radius of rotation

a_c = v^2/r = 15^2 / 3 = 75 m/s^2

Therefore

\mu = g/a_c = 9.81 / 75 = 0.1308

3 0
3 years ago
A toy rocket is launched vertically from ground level (y = 0.00 m), at time t = 0.00 s. The rocket engine provides constant upwa
Ksju [112]

The toy rocket is launched vertically from ground level, at time t = 0.00 s. The rocket engine provides constant upward acceleration during the burn phase. At the instant of engine burnout, the rocket has risen to 72 m and acquired a velocity of 30 m/s. The rocket continues to rise in unpowered flight, reaches maximum height, and falls back to the ground with negligible air resistance.

The total energy of the rocket, which is a sum of its kinetic energy and potential energy, is constant.

At a height of 72 m with the rocket moving at 30 m/s, the total energy is m*9.8*72 + (1/2)*m*30^2 where m is the mass of the rocket.

At ground level, the total energy is 0*m*9.8 + (1/2)*m*v^2.

Equating the two gives: m*9.8*72 + (1/2)*m*30^2 = 0*m*9.8 + (1/2)*m*v^2

=> 9.8*72 + (1/2)*30^2 = (1/2)*v^2

=> v^2 = 11556/5

=> v = 48.07

<span>The velocity of the rocket when it impacts the ground is 48.07 m/s</span>

3 0
3 years ago
11. A ball is thrown up and attains maximum height of 20 m. Calculate its initial speed. (g = 10 ms')
Archy [21]

final velocity = 0

acceleration = - 10 m/ s 2

distance. = 20 m

u = ?

v^2 - u ^2 = 2 a s

0^2 - u^ 2 = 2 * -10 * 20

-u^2 = -400

u = √ 400

u = 20m / s

5 0
3 years ago
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