Question

A diver exhales a bubble with volume of 250 mL at pressure of 2.4 atm and temperature of 15 C. How many gas particulate in this bubble?

Answer 1

Answer:

1.5x10²² particulates

Explanation:

Assuming ideal behaviour, we can solve this problem by using the PV=nRT formula, where:

• P = 2.4 atm

• V = 250 mL ⇒ 250 / 1000 = 0.250 L

• n = ?

• R = 0.082 atm·L·mol⁻¹·K⁻¹

• T = 15 °C ⇒ 15 + 273 = 288 K

We input the given data:

• 2.4 atm * 0.250 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 288 K

And solve for n:

• n = 0.025 mol

Finally we calculate how many particulates are there in 0.025 moles, using Avogadro's number:

• 0.025 mol * 6.023x10²³ particulates/mol = 1.5x10²² particulates