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Lorico [155]
2 years ago
11

A diver exhales a bubble with volume of 250 mL at pressure of 2.4 atm and temperature of 15 C. How many gas particulate in this

bubble?
Chemistry
1 answer:
erastova [34]2 years ago
6 0

Answer:

1.5x10²² particulates

Explanation:

Assuming ideal behaviour, we can solve this problem by using the <em>PV=nRT </em>formula, where:

  • P = 2.4 atm
  • V = 250 mL ⇒ 250 / 1000 = 0.250 L
  • n = ?
  • R = 0.082 atm·L·mol⁻¹·K⁻¹
  • T = 15 °C ⇒ 15 + 273 = 288 K

We <u>input the given data</u>:

  • 2.4 atm * 0.250 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 288 K

And <u>solve for n</u>:

  • n = 0.025 mol

Finally we <u>calculate how many particulates are there in 0.025 moles</u>, using <em>Avogadro's number</em>:

  • 0.025 mol * 6.023x10²³ particulates/mol = 1.5x10²² particulates
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#1 A

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