mol = 25/12
= 2.083 mol
1 mol = 6.02 × 10^23 atoms
2.083 mol = X
X = 2.083/1 × 6.02 × 10^23
= 1.254 × 10^24 atoms
Answer:
6.3 × 10–^4
Explanation:
Hello there!
In this case, since the rate laws are written in terms of the rate constant and the concentration of the species contributing to the rate of reaction, as this one is second order in Xe and first order in F2, the rate law would be:
![r=k[Xe]^2[F_2]](https://tex.z-dn.net/?f=r%3Dk%5BXe%5D%5E2%5BF_2%5D)
Thus, by plugging in the rate constant and concentrations, we obtain:
Best regards!
If i am not mistake u can use -log[concentration of oh-] to find it
ie -log[6.4*10^-10]=9.19
Answer:
Postulate: Gas particles are extremely small and are far apart.
The activities can be used to demonstrate the postulate is :
<u>Observing colored gas spreading into an inverted jar placed on top of a jar containing the gas</u>
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Explanation:
colored gas spreading into an inverted jar placed on top of a jar containing the gas:
This occur because of two reasons:
1. <em><u>The Gaseous particles are largely spaced . There is large distance between the gases molecule</u></em>
<em><u>2. The gases are in continuous motion . Hence they posses very high kinetic energy . This is the reason they mixes quickly if placed in a jar.</u></em>
<em><u>This occur by the process of diffusion. </u></em>
Diffusion of Gases: The intermixing of particles from the region of high concentration to low concentration.
The coloured gas goes into the space between the gaseous molecule present in the jar.(Gases are far apart)
As soon as the coloured gas is mixed in the jar , It spread quickly by diffusion because , The gaseous particles are extremely small and are far apart.
