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murzikaleks [220]
3 years ago
7

Guys please answer this

Chemistry
1 answer:
iren [92.7K]3 years ago
6 0

Answer:

Mass = 96 g

Explanation:

Given data:

Number of moles of C = 8 mol

Mass of C in gram = ?

Solution:

Formula:

Number of moles = mass/molar mass

Molar mass of C = 12 g/mol

8 mol = mass / 12 g/mol

Mass = 8 mol × 12 g/mol

Mass = 96 g

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Suppose the thermometer is miscalibrated to read .3c higher than actual. does this error in calibrations result in the molar mas
andrey2020 [161]
The answer to this question would be: too low

Molar mass would be determined by the number of mol and the mass of the object. Mass wouldn't be influenced by the temperature, but number of mol is. Using ideal gas formula of PV=nRT you can conlude that the amount of mol(n) is inversely related to the temperature (T).
If the temperature is higher than it supposed to be, then the amount of mol would be lower than it supposed to be. 
5 0
3 years ago
Consider the following reaction
aliina [53]

Answer:

d, 40 dm3.

Explanation:

According to Avogadro's law, the mole ratio of chemicals in a reaction is equal to the ratio of volumes of chemicals reacted (for gas).

From the equation, the mole ratio of N2 : H2 : NH3 = 1 : 3 : 2, meaning 1 mole of N2 reacts completely with 3 moles of H2 to give 2 moles of NH3, the ratio of volume required is also equal to 1 : 3 : 2.

Considering both N2 and H2 have 30dm3 of volume, but 1 mole of N2 reacts completely with 3 moles of H2, so we can see H2 is limiting while N2 is in excess. Using the ratio, we can deduce that 10dm3 equals to 1 in ratio (because 3 moles ratio = 30dm3).

With that being said, all H2 has reacted, meaning there's no volume of H2 left.  2 moles of NH3 is produced, meaning the volume of NH3 produced = 10 x 2 = 20 dm3. (using the ratio again)

1 mole of N2 has reacted, meaning from the  30dm3, only 10 dm3 has reacted. This also indicate that 20 dm3 of N2 has not been reacted.

So at the end, the mixture contains 20dm3 of NH3, and 20 dm3 of unreacted N2. Hence, the answer is d, 40 dm3.

7 0
3 years ago
How many grams of nacl are in 250 g of a 15.0% (by weight) solution?
Gelneren [198K]

Answer: -

37.5 g of NaCl are in 250 g of a 15.0% (by weight) solution.

Explanation: -

Total mass = 250 g

Percentage of NaCl = 15.0 %

= \frac{Number of grams of NaCl present}{total mass}

Thus \frac{15}{100} = \frac{Number of grams of NaCl present}{250g}

Number of grams of NaCl present = \frac{15 x 250g}{100}

= 37.5 g

4 0
3 years ago
There are 2 gasses, A, B. They weigh 2.46g and 0.5g respectively, and the Volume of A is 3 times the volume of B. A has a molecu
dangina [55]

Answer:

B

Explanation:

molecular mass of B is 28

8 0
2 years ago
Read 2 more answers
PLEASE PEOPLE I NEED HELP PLEASE IF YOU SEE THIS HELP ME ! :,( !!!!! PLEASEEEEEEEEE
Tems11 [23]

Answer:

year 1 is 5.5%

year 2 is 7.5%

year 3 is 10.2%

Explanation:

since,

length of the transect covered in seaweed / total lenth of transect x 100

then,

0.55 / 10.0 x 100 = 5.5

and

0.75 / 10.0 x 100 = 7.5

and

1.02 / 10.0 x 100 = 10.2

you could also just move the decimal to the right once

:)

4 0
3 years ago
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