Question

How many moles are in 3.30 x 1024 molecules of N2I6

Answer 1

Divide the number of molecules N by avogadro's constant.

Let n be the number of moles then,

$n=\frac{N}{N_A}=\frac{3.3\cdot10^{24}}{6.022\cdot10^{23}}=5.48\mathrm{mol}$

Hope this helps.