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lyudmila [28]
2 years ago
5

The Same force is applied to a 300 kg go kart and 100 kg wagon at the beginning of the race. Which time is true about their acce

leration
A. The go-kart and wagon will accelerate at the same rate

B. The go-cart and wagon will not accelerate

C. The wagon will accelerate at a faster rate

D. The go-cart with accelerate at a faster rate

Chemistry
1 answer:
murzikaleks [220]2 years ago
3 0

Answer: Well!

Explanation: I was going to answer D but fverdell82156 got to it first! So I have to agree with him! It is D!

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Ascorbic acid (vitamin
svlad2 [7]

Let us see the structure of ascorbic acid


As shown there is no COOH group however the OH group can lose a proton and forms conjugate base

The conjugate base formed is stabilized due to resonance

More the stability of conjugate base more the strength of acid

Hence ascorbic acid behaves as an acid

8 0
3 years ago
How many moles are in 35.0 grams of H₂O?
Nikitich [7]
1.94 moles


I did 35/18.02 because 18.02 is the molar mass of water
3 0
3 years ago
A sample of 42 mL of carbon dioxide gas was placed in a piston in order to maintain a constant 101 kPa of pressure.
Lilit [14]

Answer:

The answer to your question is 33.4 ml

Explanation:

Data

volume 1 = V1 = 42 ml

temperature 1 = T1 = 20°C

temperature 2 = T2 = -60°C

Volume 2 = V2 = x

Process

1.- Convert celsius to kelvin

T1 = 20 + 273 = 293°K

T2 = -60 + 273 = 233°K

2.- Use the Charles' law to solve this problem

               \frac{V1}{T1} = \frac{V2}{T2}

Solve for V2

                V2 = \frac{V1T2}{T1}

3.- Substitution

               V2 = \frac{(42)(233)}{293}

4.- Simplification

                V2 = \frac{9786}{293}

5.- Result

                V2 = 33.4ml

3 0
2 years ago
Electrical charge may be rapidly moved from one body to another by means of a(n)
Snowcat [4.5K]
<span>Conductor, and there you go, i hope this helped but if its wrong, i am extremly sorry</span>
5 0
3 years ago
Read 2 more answers
A sample of sugar (C12H22O11) contains
Oduvanchick [21]

Answer: 0.25 mol

Explanation:

Use the formula n=N/NA

n= number of mols

N =  number of particles

Nᵃ = Avogadros constant = 6.02 x

So, n=

The 10 to the power of 23 cancels out and you are left with 1.505/6.02, which is approximately 1/4. This is the same as 0.25 mol.

Hope this helped :)

5 0
3 years ago
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