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lyudmila [28]
3 years ago
5

The Same force is applied to a 300 kg go kart and 100 kg wagon at the beginning of the race. Which time is true about their acce

leration
A. The go-kart and wagon will accelerate at the same rate

B. The go-cart and wagon will not accelerate

C. The wagon will accelerate at a faster rate

D. The go-cart with accelerate at a faster rate

Chemistry
1 answer:
murzikaleks [220]3 years ago
3 0

Answer: Well!

Explanation: I was going to answer D but fverdell82156 got to it first! So I have to agree with him! It is D!

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How does a buffer resist change in ph upon addition of a strong acid?
lora16 [44]
Any buffer exists in this equilibrium
 
  HA <=> H^+ + A^-
In a buffer, there is a large reservoir of both the undissociated acid (HA) and its conjugate base (A^-) 

When a strong acid is added, it reacts with the large reservoir of the conjugate base (A^-) forming a salt and water. Since this large reservoir of the conjugate base is used, the ph does not alter drastically, but instead resist the pH change. 

8 0
3 years ago
Is how much a material opposes electric current.
krek1111 [17]

Answer:

Resistance

Explanation:

Resistance is the measure of the opposition of current in a circuit.

4 0
3 years ago
A goldsmith melts 12.4 grams of gold to make a ring. The temperature of the gold rises from 26°C to 1064°C, and then the gold me
DiKsa [7]

Problem One

You will use both m * c * deltaT and H = m * heat of fusion.

Givens

m = 12.4 grams

c = 0.1291

t1 = 26oC

t2 = 1204

heat of fusion (H_f) = 63.5 J/grams.

Equation

H = m * c * deltaT + m * H_f

Solution

H = 12.4 * 0.1291 * (1063 - 26) + 12.4 * 63.5

H = 1660.1 + 787.4

H = 2447.5 or 2447.47 is the exact answer. I have to leave the rounding to you. I have no idea where to round it although I suspect 2450 would be right for 3 sig digs.

Problem Two

Formula and Givens

t1 = 14.5

t2 = 50.0

E = 5680

c = 4.186

m = ??

E = m c * deltaT

Solution

5680 = m * 4.186 * (50 - 14.5)

5680 = m * 4.186 * (35.5)

5680 = m * 148.603 * m

m = 5680 / 148.603

m = 38.22 grams That isn't very much. Be very sure you are working in joules. You'd leave that many grams in the kettle after drying it thoroughly.

m = 38.2 to 3 sig digs.

8 0
3 years ago
Read 2 more answers
How is the oxidation state of a transition metal determined from the chemical formula ?
Vera_Pavlovna [14]

Answer:

Explanation:

In a chemical formula, the oxidation state of transition metals can be determined by establishing the relationships between the electrons gained and that which is lost by an atom.

We know that for compounds to be formed, atoms would either lose, gain or share electrons between one another.

The oxidation state is usually expressed using the oxidation number and it is a formal charge assigned to an atom which is present in a molecule or ion.

To ascertain the oxidation state, we have to comply with some rules:

  • The algebraic sum of all oxidation numbers of an atom in a neutral compound is zero.
  • The algebraic sum of all the oxidation numbers of all atoms in an ion containing more than one kind of atom is equal to  the charge on the ion.

For example, let us find the oxidation state of Cr in Cr₂O₇²⁻

This would be:  2x + 7(-2) = -2

                          x = +6

We see that the oxidation number of Cr, a transition metal in the given ion is +6.

7 0
3 years ago
Read 2 more answers
(Thermodynamics)
frutty [35]

Answer:

3853 g

Step-by-step explanation:

M_r: 107.87

         16Ag + S₈ ⟶ 8Ag₂S; ΔH°f =  -31.8 kJ·mol⁻¹

1. Calculate the moles of Ag₂S

Moles of Ag₂S = 567.9 kJ × 1 mol Ag₂S/31.8kJ = 17.858 mol Ag₂S

2. Calculate the moles of Ag

Moles of Ag = 17.86 mol Ag₂S × (16 mol Ag/8 mol Ag₂S) = 35.717 mol Ag

3. Calculate the mass of Ag

Mass of g = 35.717 mol Ag × (107.87 g Ag/1 mol Ag) = 3853 g Ag

You must react 3853 g of Ag to produce 567.9 kJ of heat

3 0
3 years ago
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