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-BARSIC- [3]
3 years ago
15

A balloon inflated in a room at 25oC has a volume of 3.00 L. If the balloon is heated at a constant pressure, at what temperatur

e will the volume of the balloon double?
1. 596 K
2. 323 K
3. 298 K
4. 149 K
Chemistry
1 answer:
Alexeev081 [22]3 years ago
8 0

Answer:

596K

Explanation:

Using Charles law equation;

V1/T1 = V2/T2

Where;

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question,

V1 = 3.00 L

V2 = double of V1 = 2 × 3.00 = 6.00 L

T1 = 25°C = 25 + 273 = 298K

T2 = ?

Using V1/T1 = V2/T2

3/298 = 6/T2

Cross multiply

298 × 6 = 3 × T2

1788 = 3T2

T2 = 1788 ÷ 3

T2 = 596K

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posledela

Answer:

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Explanation:

I am assuming that you are asking for confirmation on your answer. The answer is 5.65.

You would do:

[pOH] = -log[OH-]

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To find pH your would subtract the pOH from 14.

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3 years ago
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m(Na) = 98900 mg.
n - amount of substance.
m - mass of substance.
M - molar mass of substance.
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Hope this helps :)

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