Question

A ball is thrown horizontally from the top of a 73.9-m building and lands 183 m from the base of the building. Ignore air resistance. How long is the ball in the air

Answer 1

Answer:

t = 3.88 seconds

Explanation:

Given that,

A ball is thrown horizontally from the top of a 73.9-m building and lands 183 m from the base of the building.

We need to find the time for which the ball is in air. Let the time be t.

$y=y_o+ut+\dfrac{1}{2}at^2$

Here, a = -g, $y_o=73.9\ m$ and y = 0

u is initial velocity, u = 0

$y_o=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2y_o}{g}}\\\\t=\sqrt{\dfrac{2\times 73.9}{9.8}}\\\\t=3.88\ s$

So, the ball is in the air for 3.88 seconds.