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iren [92.7K]
3 years ago
11

A ball is thrown horizontally from the top of a 73.9-m building and lands 183 m from the base of the building. Ignore air resist

ance. How long is the ball in the air
Physics
1 answer:
user100 [1]3 years ago
6 0

Answer:

t = 3.88 seconds

Explanation:

Given that,

A ball is thrown horizontally from the top of a 73.9-m building and lands 183 m from the base of the building.

We need to find the time for which the ball is in air. Let the time be t.

y=y_o+ut+\dfrac{1}{2}at^2

Here, a = -g, y_o=73.9\ m and y = 0

u is initial velocity, u = 0

y_o=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2y_o}{g}}\\\\t=\sqrt{\dfrac{2\times 73.9}{9.8}}\\\\t=3.88\ s

So, the ball is in the air for 3.88 seconds.

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Answer:

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As per the question:

The following reading of an inverted staff is given as:

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