1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sertanlavr [38]
3 years ago
6

Two resistors of 12Ω and 2Ω are connected in parallel to a battery of 4 V. Current through 12Ω resistor will be _____________ an

d power dissipated at 2Ω resistor will be ??​
Physics
1 answer:
Alex3 years ago
6 0

Answer:

0.33  Amp

8 Watts

Explanation:

The current through the 12 Ω resistor will be given by Ohm's law:

4 V / 12 Ω = 1/3 Amp ≈ 0.33  Amp

The power dissipated on the 2 Ω resistor can be calculated via the formula: \frac{V^2}{R}  which gives:

4^2 / 2 = 8 Watts

You might be interested in
Cold air can hold more moisture than warm air<br><br> true<br> false
sattari [20]
The answer is false

hope this helps
8 0
4 years ago
Read 2 more answers
Once cells with nuclei developed, organisms were able to become more complex, which allowed them to adapt to the conditions in m
liq [111]
D). natural selection i am not sure tho
4 0
3 years ago
Read 2 more answers
How will you connect 3 cells each of value 2V to give a total of 3V * Two in parallel with one in series Two in series with one
emmainna [20.7K]

Answer:

<em>two of them in series with one in parallel</em>

Explanation:

When two or more batteries are connected in

(a) series: the total voltage produced is equal to the sum of the voltages on each of the batteries. For example, if two batteries A and B of 3V and 2V respectively are connected in series, then the total voltage produced is

3V + 2V = 5V

(b) parallel: the total voltage produced is equal to the voltage on any one of the batteries. As a mention, only batteries of the same voltage should be connected together in parallel. For example, if two batteries A and B each of 4V are connected together in parallel, then the total voltage produced is 4V.

If these batteries are not of the same voltage, then the one of larger voltage will charge the one of the lower voltage until they both have the same voltage. That means that their eventual voltage will be the average of their voltages. For example, if two batteries A and B of 3V and 2V respectively, are connected in parallel, their total voltage will be,

(3V + 2V) / 2 =2.5V

Now, from the question.

Since there are three cells each of value 2V.

=>If we connect two of them in series, the total voltage from those two cells will be 2V + 2V = 4V

=>If we then connect this series connection in parallel with the third cell, then we have a parallel combination of 4V and 2V. Since they have different voltages, then the total voltage will be the average of the two voltages. i.e

(4V + 2V) / 2 = 6 / 2 = 3V

Therefore, to have a total of 3V from three cells each of 2V, we need to connect <em>two of them in series with one in parallel</em>

<em></em>

<em></em>

5 0
3 years ago
In order to attain orbit around earth, the ATLAS-V rocket must accelerate up to a
IrinaK [193]
A) average acceleration = final velocity - initial velocity / time

= 7700 - 0 / 11

= 700ms^-2


B) force = mass x acceleration

= (3.05 x 105) x 700

= 320.25 x 700

= 224,175N
7 0
3 years ago
Suppose the rocket in the Example was initially on a circular orbit around Earth with a period of 1.6 days. Hint (a) What is its
ruslelena [56]

Answer:

a

The orbital speed is v= 2.6*10^{3} m/s

b

The escape velocity of the rocket is  v_e= 3.72 *10^3 m/s

Explanation:

Generally angular velocity is mathematically represented as

            w = \frac{2 \pi}{T}

Where T is the period which is given as 1.6 days = 1.6 *24 *60*60 = 138240 sec

       Substituting the value

         w = \frac{2 \pi}{138240}

             = 4.54*10^ {-5} rad /sec

At the point when the rocket is on a circular orbit  

   The gravitational force =  centripetal force and this can be mathematically represented as

              \frac{GMm}{r^2} = mr w^2

Where  G is the universal gravitational constant with a value  G = 6.67*10^{-11}

            M is the mass of the earth with a constant value of M = 5.98*10^{24}kg

            r is the distance between earth and circular orbit where the rocke is found

               Making r the subject

                     r = \sqrt[3]{\frac{GM}{w^2} }

                        = \sqrt[3]{\frac{6.67*10^{-11} * 5.98*10^{24}}{(4.45*10^{-5})^2} }

                        = 5.78 *10^7 m

The orbital speed is represented mathematically as

                   v=wr

Substituting value

                  v= (5.78*10^7)(4.54*10^{-5})

                     v= 2.6*10^{3} m/s    

The escape velocity is mathematically represented as

                            v_e = \sqrt{\frac{2GM}{r} }

Substituting values

                             = \sqrt{\frac{2(6.67*10^{-11})(5.98*10^{24})}{5.78*10^7} }

                             v_e= 3.72 *10^3 m/s

7 0
3 years ago
Other questions:
  • The reaction between nitrogen and hydrogen to produce ammonia is described as an equilibrium reaction. what substances are prese
    9·2 answers
  • A student on an amusement park ride moves in a
    11·1 answer
  • Dropping a temporary magnet on the floor may destroy its magnetism because _____. the floor absorbs the magnetic field the domai
    15·1 answer
  • I'm not really good on this type of stuff :(
    6·1 answer
  • What phase difference between two otherwise identical traveling waves, moving in the same direction along a stretched string, wi
    7·1 answer
  • An ultrasound pulse has a wavelength of 1.0mm. Its speed in water is 1400m. What’s the frequency?
    12·1 answer
  • 23. In an attempt to escape his island, Gilligan builds a raft and sets to sea. The wind shifts a great deal during the day, and
    10·1 answer
  • I’m confused how do you right that in OZ someone please help I have to turn it in
    15·1 answer
  • FIRST ANSWER GET'S BRAINLIEST!!!!
    14·2 answers
  • A student conducts an experimenting to test how the temperature of a ball affects its bounce height. The same ball is used for e
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!