1pt If the room is the frame of reference for the study of an object moving in three dimensions, from where should distances be
measured?
O A. one wall and the floor
OB. two walls and the floor
O c. the floor and the ceiling
O D. the door
O A. one wall and the floor
OB. two walls and the floor
O c. the floor and the ceiling
O D. the door
1 answer:
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Answer:
162500000.
Explanation:
Given that
Diameter of the wire , d= 1.8 mm
The length of the wire ,L = 15 cm
Current ,I = 260 m A
The charge on the electron ,e= 1.6 x 10⁻¹⁹ C
We know that Current I is given as
I=Current
q=Charge
t=time
q= I t
q= 260 m t
The total number of electron = n
q= n e
n=162500000 t
The number of electron passe per second will be 162500000.
Integrating the velocity equation, we will see that the position equation is:
Let the velocity of the particle is:
To get the position equation we just need to integrate the above equation:
Then:
Replacing that in our integral we get:
Where C is a constant of integration.
Now we remember that
Then we have:
To find the value of C, we use the fact that f(0) = 0.
C = -1 / 3
Then the position function is:
Integrating the velocity equation, we will see that the position equation is:
To learn more about motion equations, refer to:
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