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malfutka [58]
3 years ago
6

1pt If the room is the frame of reference for the study of an object moving in three dimensions, from where should distances be

measured?
O A. one wall and the floor
OB. two walls and the floor
O c. the floor and the ceiling
O D. the door

Physics
1 answer:
oksian1 [2.3K]3 years ago
5 0

Answer:

Option B, two walls and the floor

Explanation:

The distance should be measured from the point where at least the three axed meet.

Two walls and the floor are equivalent to three axes.

Vertical wall 1 = Y Axis

Horizontal wall2 = X Axis

Floor = Z Axis

Thus, the distance should be measured from the point where two walls and one floor meet.

Option , B is correct

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Answer:

Hydrogen ions contains +1 charge while sulphate ions have 2 charge. ... No .of ions in one formula unit of MgC12 =3 Total no of ions in MgC12 =1.20x1024 x3=3.6x1024 ions.

Explanation:

8 0
3 years ago
A reaction that releases energy as it occurs is classified as a(n ________.
cluponka [151]
The reaction that releases energy is called an EXOTHERMIC process. This is a word from the prefix exo- which means to exit and from the root word therm which is a unit of heat which in turn is form of energy. This is the opposite process of ENDOTHERMIC process. 
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A car drives 16 miles south and then 12 miles west. What is the magnitude of the car's displacement?
Brut [27]

Answer:

The answer is 20 miles

Explanation:

You would use a^2+b^2=c^2 to get the displacement.

So 16^2+12^2=c^2

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8 0
3 years ago
A 1.0-kg block moving to the right at speed 3.0 m/s collides with an identical block also moving to the right at a speed 1.0 m/s
____ [38]

Answer:

Speed of both blocks after collision is 2 m/s

Explanation:

It is given that,

Mass of both blocks, m₁ = m₂ = 1 kg

Velocity of first block, u₁ = 3 m/s

Velocity of other block, u₂ = 1 m/s

Since, both blocks stick after collision. So, it is a case of inelastic collision. The momentum remains conserved while the kinetic energy energy gets reduced after the collision. Let v is the common velocity of both blocks. Using the conservation of momentum as :

m_1u_1+m_2u_2=(m_1+m_2)v

v=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}

v=\dfrac{1\ kg\times 3\ m/s+1\ kg\times 1\ m/s}{2\ kg}

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7 0
3 years ago
If a net force of 800n is acting on an object with a mass of 60kg. What would be the objects accelerations
aivan3 [116]

Answer: 13.33 m/s^2

Explanation:

Force is the product of mass of an object and its acceleration.

i.e Force = Mass x Acceleration

Since Force on object = 800N

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Then, Force = Mass x Acceleration

800N = 60Kg x Acceleration

Acceleration = (800N/60kg)

Acceleration = 13.33 m/s^2 (The unit of acceleration is metre per second square)

Thus, the objects accelerations is 13.33 m/s^2

5 0
4 years ago
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