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Digiron [165]
3 years ago
10

Steel beams are used for load bearing supports in a building. Each beam is 4.0 m long with a cross-sectional area of 7.5 10-3 m2

and supports a load of 4.5 104 N. Young's modulus for steel is 210 ✕ 109 N/m2.
Physics
1 answer:
dsp733 years ago
3 0
Yes I think he was just asking me if you
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A football player runs from his own goal line to the opposing team's goal line returning to the fifty yard line all i 18.0s calc
ANTONII [103]
<span>assuming the pitch is 100yards long, the player runs 100yards to the other goal then a further 50 yards back to the 50-yard line. So he/she runs 150yards in 18s
150/18 = 8.33yards per second average speed.
Initial velocity = 0, average velocity =8.33
Vav = (Vinitial+Vfinal)/2
Vav = 4.16m/s</span>
3 0
4 years ago
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Question 15 of 25
vichka [17]
Answer: conduction :it transfers heat between objects that are in direct contact with eachother
7 0
3 years ago
A spring-loaded toy gun is used to shoot a ball of mass 1.5 kg straight up in the air, as shown. The spring has spring constant
asambeis [7]

Answer:

Part a)

U = 15.5 J

Part b)

h = 1.05 m

Part c)

v = 4.55 m/s

Explanation:

Part a)

Initial potential energy stored in the spring is given by

U = \frac{1}{2}kx^2

now we have

k = 777 N/m

x = 20.0 cm

now from above formula we will have

U = \frac{1}{2}(777)(0.20)^2

U = 15.5 J

Part b)

By mechanical energy conservation law we can say that initial spring potential energy stored = final gravitational potential energy at the top position

\frac{1}{2}kx^2 = mgh

15.5 = 1.5(9.8)h

h = 1.05 m

So maximum height from gun is 1.05 m

Part c)

For muzzle velocity of the ball we can use the energy conservation again

According to which the final kinetic energy of the ball = initial spring energy stored in it

\frac{1}{2}mv^2 = \frac{1}{2}kx^2

(\frac{1}{2})(1.5 v^2) = 15.5

v = v = 4.55 m/s

4 0
3 years ago
Which is a complex molecule? <br> A. H2 <br> B. Ne <br> C. CO <br> D. H2O
madam [21]
The answer should be D. H2O
4 0
3 years ago
Read 2 more answers
PLEASEEEE HELP
den301095 [7]

Answer:

Wavelength of light in  diamond λ2 = 179.75 nm (Approx.)

Explanation:

Given:

Blue light of wavelength λ1 = 435 nm

n2 in diamond = 2.42

Find:

Wavelength of light in  diamond λ2

Computation:

Since the wavelength is smaller, the frequency stays constant. The frequency of vibrations does not shift when they pass from one source to the next.

So,

n1λ1 = n2λ2

(1)(435) = (2.42)λ2

Wavelength of light in  diamond λ2 = 179.75 nm (Approx.)

8 0
3 years ago
Read 2 more answers
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